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About me

I have always enjoyed tutoring. I find that it gives me a real job satisfaction to see a child or student you have helped feel much more confident. Having worked at a tutoring company, Explore learning, for about 2 years now, I have very good communication skills and a lot of experience working with children of all ages.

When it comes to mathematics, I believe that being able to understand the method is just as, if not more, important than being able to answer the question. I love finding different ways to solve puzzles and maths is the best subject for this. There are always a set of logical steps to get the answer. Helping the student understand the problem, rather than just telling them how to do it, prevents the same mistakes from copping up over and over again.

If you would like to arrange a meet-the-tutor session, please message me before booking so we can arrange a convenient time.You can find my availability on my profie.

Subjects offered

SubjectLevelMy prices
Further Mathematics A Level £24 /hr
Maths A Level £24 /hr
Further Mathematics GCSE £22 /hr
Maths GCSE £22 /hr

Qualifications

QualificationLevelGrade
MathematicsA-LevelA*
Further MathematicsA-LevelA
PhysicsA-LevelA
MusicA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

General Availability

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Please get in touch for more detailed availability

Ratings and reviews

4.9from 51 customer reviews

Nick (Parent) November 17 2016

great

Aaron (Student) November 10 2016

Was very helpful with my needs and was very kind and polite also. Definitely recommended.

Karen (Parent) May 13 2016

Very helpful and Guy passed the all important GCSE in Maths!

Deborah (Parent) June 3 2016

Barnaby really helped my daughter...so much that she got a B in her GCSE Maths. He is very understanding and he made his explanations simply to understand. We can't thank him enough, would highly recommend and we wish him well in the future too.
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Questions Barnaby has answered

How do I integrate by parts?

Lets use and example: y=x*sin(x). If we try to integrate this normally, we find it very hard. The integration by parts method splits up the function we are integrating into manageable bits. The formula we use to work this out is: Integral(U*dV)=U*V-Integral(V*dU) were the dU is the differenti...

Lets use and example: y=x*sin(x). If we try to integrate this normally, we find it very hard. The integration by parts method splits up the function we are integrating into manageable bits. The formula we use to work this out is:

Integral(U*dV)=U*V-Integral(V*dU)

were the dU is the differential of U and dV is the differential of V. In our example y=x*sin(x), we let U=x and dV=sin(x). To find dU we differentiate x (dU=1). To find V we integrate dV (V=-cos(x)). Now we just stick everything in the formula:

Integral(xsin(x))= x*(-cos(x))-Integral((-cos(x))*1)=-x*cos(x)+sin(x) +C

where C is an arbitrary constant. This is the answer.

- See more at: https://www.mytutorweb.co.uk/tutors/secure/ta-yourexplanations.html#sthash.JreWATFA.dpuf

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2 years ago

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