Currently unavailable: until 20/09/2015
Degree: Mechanical Engineering (Masters) - Durham University
Hi, I’m Toby and I’ve just graduated from Durham University with a Masters in Engineering.
I’m offering tuition in GCSE Physics and GCSE & A Level Maths, for all exam boards.
I’d love to share my knowledge and enthusiasm with my tutees. Having studied Maths, Further Maths and Physics at A-Level I have an extensive knowledge of the subject matter and a variety of learning techniques.
I like to keep things informal, laid-back and relaxed so that students feel they can ask any question. As a tutor, my sessions will be adapted to whatever it is that you want to learn: exam technique, tricky concepts from class or topics on the specification that you’re unsure about.
As a qualified ski-instructor I have a number of years teaching experience and am patient and clear in my explanations. I aim to pass on my enthusiasm for maths and science in a fun and creative way.
Please don’t hesitate to contact me for either a tutorial or a free meet the tutor session.
I'm currently available throughout the week and am flexible with timings.
|Further Mathematics||A Level||£24 /hr|
|Maths||A Level||£24 /hr|
|Mechanical Engineering||Masters Degree||1st|
Paula (Parent) March 19 2015
Jacqueline (Parent) April 30 2015
Maree (Parent) April 16 2015
Maree (Parent) April 11 2015
Solving Simultaneous Equations
Equation 1: 6x + 2y = 2
Equation 2: 5x - 7y = 6.
Find x and y.
1) Check is if it is possible to solve. Here we have 2 unknowns, x and y, and 2 equations, therefore it is possible to solve. (If there are more unknowns than equations then it is not possible to solve.)
2) Eliminate an unknown in one of the equations.
- Rearrange each equation to get the x terms on one side and the y terms on the other.
Eq 1 .... 6x=2-2y
Eq 2 .... 5x=6+7y
- Look for a common multiple for the coefficients (number in front of the unknown) of x, e.g. 30. So we multiply each equation up to get 30x on one side, then we can say equation 1 equals equation 2.
5 x Eq 1 .... 30x=10-10y .... we will call this Eq 3
6 x Eq 2 .... 30x=36+42y .... we will call this Eq 4
- Remember what you do to one side of the equation you must do to the other.
3) Now both Eq3 and Eq4 are of the form 30x=.... we can say that Eq3=Eq4.
10-10y = 36+42y
4) Now just solve as you would normally to find y=-0.5.
5) Put this value of y into Eq1 to find x=0.5.
6) Put both these values into Eq2 to check result, e.g. 6*0.5 + 2*-0.5 = 3 - 1 = 2.
This is correct therefore we have the correct answer.