Zachary H. A Level Maths tutor, GCSE Maths tutor, Mentoring .STEP. tu...

Zachary H.

£18 - £25 /hr

Currently unavailable: for regular students

Studying: Mathematics (Masters) - Manchester University

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About me

In any problem, there are multiple ways of approach and I will show a variety until I find one that resonates with the individual. I aim to help the tutee understand the concepts introduced and how to present their answer. The downfall of many students comes from the fact that they apply formulae incorrectly or misunderstand their purpose lower down the school system and in uni admissions fail to make the leap in logical reasoning. I have studied maths under WJEC and AQA as well as sitting STEP and MAT exams. I have previous tutoring experience with secondary school students. I strive to push the limits of your understanding to make you more comfortable with concepts that seem alien on their own.

In any problem, there are multiple ways of approach and I will show a variety until I find one that resonates with the individual. I aim to help the tutee understand the concepts introduced and how to present their answer. The downfall of many students comes from the fact that they apply formulae incorrectly or misunderstand their purpose lower down the school system and in uni admissions fail to make the leap in logical reasoning. I have studied maths under WJEC and AQA as well as sitting STEP and MAT exams. I have previous tutoring experience with secondary school students. I strive to push the limits of your understanding to make you more comfortable with concepts that seem alien on their own.

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Qualifications

SubjectQualificationGrade
MathematicsA-level (A2)A*
Further MathematicsA-level (A2)A
PhysicsA-level (A2)A
ChemistryA-level (A2)B
STEP1Uni admission test2
STEP2Uni admission test3
STEP3Uni admission test3

Subjects offered

SubjectQualificationPrices
MathsA Level£20 /hr
MathsGCSE£18 /hr
.MAT.Uni Admissions Test£25 /hr

Questions Zachary has answered

In integration, what does the +c mean and why does it disappear if you have limits?

Integration is the opposite to differentiation, when you differentiate with a constant it disappears and so you have to add it back when you integrate. You know what shape it is, but you don't know how far up the y axis it is. That's what the +c signifies. 

+c disappears when you have limits because you add it in the upper limit and you take it away in the lower limit, no matter what the values of x. For example, if you were to integrate x between 2 and 3, you'd have to evaluate [(x^2)/2 + c] between the values of 2 and 3. 

You'd get [(3^2)/2 + c] - [(2^2)/2 + c]
This is the same as (9/2) - (4/2) + c - c = 5/2

This is true no matter what x you put in because +c isn't changed by x in any way.

Integration is the opposite to differentiation, when you differentiate with a constant it disappears and so you have to add it back when you integrate. You know what shape it is, but you don't know how far up the y axis it is. That's what the +c signifies. 

+c disappears when you have limits because you add it in the upper limit and you take it away in the lower limit, no matter what the values of x. For example, if you were to integrate x between 2 and 3, you'd have to evaluate [(x^2)/2 + c] between the values of 2 and 3. 

You'd get [(3^2)/2 + c] - [(2^2)/2 + c]
This is the same as (9/2) - (4/2) + c - c = 5/2

This is true no matter what x you put in because +c isn't changed by x in any way.

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3 years ago

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