Chris W. A Level Maths tutor, GCSE Maths tutor, A Level Further Mathe...

Chris W.

Unavailable

Mathematics (Bachelors) - Durham University

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1 completed lesson

About me

About you:
  • I have done mentoring previously; from being a one-to-one reading mentor, to tutoring whole class for GCSE Maths.
  • My passion for maths and sciences has always been there; which is why I chose physics modules as well as maths modules here at Durham.
  • I fully understand the A-Level syllabus and exam techniques required to get an A*; as shown by my four A* grades at A-Level.
 
The session:
  • My sessions will focus on me delivering a short and concise run through of the material and then move on to exam questions, slowly offering help as we tactle the problem together.
  • This is the style of tutorials at university and I think it is a fantastic way of improving. Though I can change my style to suit individuals as everyone learns differently.
  • A optional bonus question of greater difficulty will be available, whether this is for homework, or a problem just to think about before next session is completely up to you. I will reveal the answer at the start of the next session.
 
Anything else:
  • Please do not hesitate to contact me about any questions!
 
About you:
  • I have done mentoring previously; from being a one-to-one reading mentor, to tutoring whole class for GCSE Maths.
  • My passion for maths and sciences has always been there; which is why I chose physics modules as well as maths modules here at Durham.
  • I fully understand the A-Level syllabus and exam techniques required to get an A*; as shown by my four A* grades at A-Level.
 
The session:
  • My sessions will focus on me delivering a short and concise run through of the material and then move on to exam questions, slowly offering help as we tactle the problem together.
  • This is the style of tutorials at university and I think it is a fantastic way of improving. Though I can change my style to suit individuals as everyone learns differently.
  • A optional bonus question of greater difficulty will be available, whether this is for homework, or a problem just to think about before next session is completely up to you. I will reveal the answer at the start of the next session.
 
Anything else:
  • Please do not hesitate to contact me about any questions!
 

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Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

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Qualifications

SubjectQualificationGrade
MathsA-level (A2)A*
Further MathsA-level (A2)A*
PhysicsA-level (A2)A*
ChemistryA-level (A2)A*

Subjects offered

SubjectQualificationPrices
Further MathematicsA Level£20 /hr
MathsA Level£20 /hr
ChemistryGCSE£18 /hr
MathsGCSE£18 /hr
PhysicsGCSE£18 /hr
ScienceGCSE£18 /hr
-Personal Statements-Mentoring£22 /hr
.STEP.Uni Admissions Test£25 /hr

Questions Chris has answered

How do I find the equation of a line connecting points a(p,q) and b(r,s)?

First we need to find the gradient of the line connecting points a and b:
gradient m = (change in y)/(change in x) = (q - s)/(p -r)

Now we use the following equation:

y - y1 = m(x - x1)

substituting suitable values for (x1, y1) (can be points a or b but we'll use point a this time) and m (calculated above):

Using point a:

y - q = [(q-s)/(p-r)](x - p)

and so the equation in the form y = f(x) is:
y = [(q-s)/(p-r)]x + [(q-s)/(p-r)](-p) + q

First we need to find the gradient of the line connecting points a and b:
gradient m = (change in y)/(change in x) = (q - s)/(p -r)

Now we use the following equation:

y - y1 = m(x - x1)

substituting suitable values for (x1, y1) (can be points a or b but we'll use point a this time) and m (calculated above):

Using point a:

y - q = [(q-s)/(p-r)](x - p)

and so the equation in the form y = f(x) is:
y = [(q-s)/(p-r)]x + [(q-s)/(p-r)](-p) + q

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4 years ago

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