Hayk Y. A Level Further Mathematics  tutor, A Level Maths tutor, GCSE...

Hayk Y.

Currently unavailable: no new students

Degree: MSci Mathematics (Bachelors) - Imperial College London University

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About me

I am a reliable and driven individual who is extremely passionate about tutoring. Having finished school only recently, I know first hand about the limitations of the big classsroom environment, hence why I have a strong admiration for one to one tution. Education should not have to be a chore, but it ought to be enoyable and rewarding for tutors and tutees alike. All it takes is committment from both parties and that in itself is a recipe for success.

As you would have guessed by now, Mathematics is my passion. I live, breathe and sleep Mathematics, and my enthusiaism for my subject area only helps me be a better tutor. It is therefore my aim to get my students to be as passionate about what they are studying as I am, making them truly engage in what they are doing.

Though I am a Mathematician by day, I am most certainly a rounded individual by night; meaning that I am able to communicate appropriately in a relaxed learning environment. I thoroughly enjoy witnessing people succeed and to be able to positively contribute to this success is just an added bonus.

Subjects offered

SubjectLevelMy prices
Further Mathematics A Level £20 /hr
History A Level £20 /hr
Maths A Level £20 /hr
History GCSE £18 /hr
Maths GCSE £18 /hr

Qualifications

QualificationLevelGrade
MathematicsA-LevelA*
Further MathematicsA-LevelA*
HistoryA-LevelA
Philosophy and EthicsA-LevelA
Law ASA-LevelA
AEA MathematicsUni Admissions TestDistinction
STEP IUni Admissions Test1
STEP IIUni Admissions Test2
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: no new students

Questions Hayk has answered

How can we determine stationary points by completing the square?

Suppose we have completed the square on y=ax^2+bx+c and attained y=a(x+p)^2+q, where a,b,c,p,q are real numbers with 'a' not equal to zero and p,q can be expressed in terms of a,b,c. For a>0 we have a minimum point, where x takes a value such that a(x+p)^2+q is smallest, giving x= -p and hence...

Suppose we have completed the square on y=ax^2+bx+c and attained y=a(x+p)^2+q, where a,b,c,p,q are real numbers with 'a' not equal to zero and p,q can be expressed in terms of a,b,c. For a>0 we have a minimum point, where x takes a value such that a(x+p)^2+q is smallest, giving x= -p and hence y=q. For a<0, we have a maximum point, where x takes a value such that a(x+p)^2+q is biggest, also giving x= -p and hence y=q. 

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2 years ago

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