PremiumZeeshan A. GCSE Maths tutor, A Level Physics tutor, A Level Maths tut...
£22 - £24 /hr

Zeeshan A.

Degree: Theoretical Physics with Applied Maths (Masters) - Birmingham University

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About me

Hi,

I myself am studying Theoretical Physics with Applied Maths in the University of Birmingham, and I would absolutely love tutoring (especially Maths!).

I am very patient and motivated - since I know that understanding some concepts can be daunting at GCSE  and A-level.

I aim to understand the student's position whilst approaching concepts in a logical manner at an appropriate pace. Provided I am informed in advance of the topic for an arranged lesson, I will give my time to prepare fully around it before the sessions. And/Or if there are any questions or past-paper help I will guide through the important facts through the paper.

In any case, more importantly, I believe the tutee him/herself should lead the sessions, if they are going to be effective.

Normally in the sessions I would give explanations along with worked examples discussing with the tutee.

In the midst I would ask reasonably progressive questions to make sure the tutee can understand the relevant concepts. 

 I also achieved Silver Award in the Maths Challenge in my year 12.

Availability: Available most evenings except Monday evenings

Subjects offered

SubjectLevelMy prices
Further Mathematics A Level £24 /hr
Maths A Level £24 /hr
Physics A Level £24 /hr
Maths GCSE £22 /hr

Qualifications

QualificationLevelGrade
MathematicsA-LevelA*
Further MathsA-LevelA
PhysicsA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

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Please get in touch for more detailed availability

Ratings and reviews

4.9from 18 customer reviews

Luke (Student) October 26 2015

Very helpful and patient, Thanks

Sheeru (Student) April 26 2015

He is excellent. Very helpful.

Iftikhar (Parent) March 31 2015

Really an amazing tutor. Has helped me so much! Very dependable, patient and clearly explains all questions and answers.

Sheeru (Student) April 4 2015

He is excellent. Very helpful.
See all reviews

Questions Zeeshan has answered

How to derive the formula for a geometric series sum

Any geometric series is defined by an initial term a, and a common ratio b.  This means that we start with a and multiply by b to get each next term. And so the general geometric series is written: a*r^0,a*r^1,a*r^2,a*r^3,...,a*r^n ; where n+1 = no. of terms. Now the sum of the above, S is: ...

Any geometric series is defined by an initial term a, and a common ratio b

This means that we start with a and multiply by b to get each next term.

And so the general geometric series is written:

a*r^0,a*r^1,a*r^2,a*r^3,...,a*r^n ; where n+1 = no. of terms.

Now the sum of the above, S is:

S = a*r^0+a*r^1+a*r^2+a*r^3+...+ar^n

Factorise r out in most terms in right hand side:

S = a*r^0+r*(a*r^0+a*r^1+a*r^2+...+a*r^(n-1))

Now note that the sum within the brackets includes all terms in our original sum S, save the last term a*r^n. This means we can substitute (S-a*r^n) for it. Therefore,

S = a*r^0+r*(S-a*r^n)

Now all we are left to do is make the value of the sum, S, the subject of the equation:

S = a+r*S-a*r^(n+1)

S-r*S = a-a*r^(n+1)

S*(1-r) = a*(1-r*(n+1)); factorize S on LHS, and a on RHS.

S = a*(1-r*(n+1))/(1-r)

 

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2 years ago

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