Nita B.

Unavailable

BSc Accounting and Finance (Bachelors) - Bristol University

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Hi! I'm Nita, second year Accounting and Finance student at the University of Bristol. I am keen on sharing my experiences and help out in Maths at GCSE level.

Hi! I'm Nita, second year Accounting and Finance student at the University of Bristol. I am keen on sharing my experiences and help out in Maths at GCSE level.

#### Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

Enhanced DBS Check

12/11/2014

#### Qualifications

EconomicsA-level (A2)A*
MathematicsA-level (A2)A

#### Subjects offered

SubjectQualificationPrices
MathsA Level£20 /hr
MathsGCSE£18 /hr

### Surd Calculations?

Surds are numbers left in 'square root form' (or 'cube root form' etc). They are therefore irrational numbers. Surds are the root of numbers and not whole numbers.

Multiplication

Example:

√2 × √6 = √12 (= 2× 6)

= √4 × √3

= 2√3

4√3 - 2√3 = 2√3

5√5 + 8√5 = 13√5

Note: 5√7 + 3√3 cannot be manipulated because the surds are different (one is √7 and one is √3)

Example:

Simplify √12 + √27

12 = 3 × 4. So √12 = √(3 × 4) = √3 × √4 = 2 × √3.

Similarly, √27 = 3√3.

Hence √12 + √27 = 2√3 + 3√3 = 5√3

Surds are numbers left in 'square root form' (or 'cube root form' etc). They are therefore irrational numbers. Surds are the root of numbers and not whole numbers.

Multiplication

Example:

√2 × √6 = √12 (= 2× 6)

= √4 × √3

= 2√3

4√3 - 2√3 = 2√3

5√5 + 8√5 = 13√5

Note: 5√7 + 3√3 cannot be manipulated because the surds are different (one is √7 and one is √3)

Example:

Simplify √12 + √27

12 = 3 × 4. So √12 = √(3 × 4) = √3 × √4 = 2 × √3.

Similarly, √27 = 3√3.

Hence √12 + √27 = 2√3 + 3√3 = 5√3

3 years ago

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