Sophie A. A Level Economics tutor, GCSE Geography tutor, GCSE Maths t...

Sophie A.

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Degree: Economics (Bachelors) - Exeter University

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About me

Hi, I'm Sophie and I am currently studying Economics at Exeter University. I have 2 years of past experience tutoring maths and english at a tutoring centre to a variety of ages.

I am available to tutor:

 - GCSE Mathematics

 - GCSE Geography

 - A Level Economics

All 3 subjects I have earned high grades in myself, but more importantly I enjoy each one enormously and would love to help you with any problems you may have in them.

In a session with me, I will focus on what you want to learn or revise, I will use example questions, as well as giving you top tips that I found useful for these subjects' exams.

Of course you are also more that welcome to provide any questions you may be finding tricky, and I will endeavour to help you.

 

I look forward to meeting you soon!

 

Sophie

 

Subjects offered

SubjectLevelMy prices
Economics A Level £20 /hr
Geography GCSE £18 /hr
Maths GCSE £18 /hr

Qualifications

QualificationLevelGrade
EconomicsA-LevelA*
MathsA-LevelA
GeographyA-LevelA*
Disclosure and Barring Service

CRB/DBS Standard

09/11/2012

CRB/DBS Enhanced

No

Currently unavailable: no new students

Questions Sophie has answered

How do I solve fractions with unknowns in the denominators?

To solve the equation: (5x+3)/(x) + x = 1, where (x) is the denominator, we have to convert the equation into an equation without any denominators. To do this, we multiply each variable by (x), so the equation becomes: (5x+3) + (x)(x) = (1)(x). The next step is to expand the brackets: 5x + 3 ...

To solve the equation: (5x+3)/(x) + x = 1, where (x) is the denominator, we have to convert the equation into an equation without any denominators.

To do this, we multiply each variable by (x), so the equation becomes: (5x+3) + (x)(x) = (1)(x).

The next step is to expand the brackets: 5x + 3 + x^2  = x

After this, we move all variables onto one side of the equation (by subtracting x from both sides) so that it equals 0: x^2 + 4x + 3 = 0 

Factorsing this equation we get: (x + 3)(x + 1) = 0

Therefore, we can equate each bracket to 0, giving the solutions for x:

x + 3 = 0, x = -3

x + 1 = 0, x = -1

 
 
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2 years ago

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