Anna H. GCSE Biology tutor, A Level Biology tutor, GCSE Maths tutor, ...

Anna H.

Currently unavailable: for regular students

Degree: Natural Sciences (Bachelors) - Durham University

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About me

Hi,

My name is Anna Hutchinson and I am 19 years old. I am studying Natural Sciences (Maths and Biology) at Durham University. 

I have tutored in the past, both at school and University and I find it easy to adapt my teaching style in order to suit the student. I understand it may be hard to grasp particular topics and this can get frustrating! As a result I always have a few tricks up my sleeve to help make the topic seem a bit more straight forward. 

After getting two A*s and an A in my A-Levels I thoroughly understand the subjects I am offering and my passion for them often spreads to my tutees.

I am very friendly and approachable and would love to help you (or your child) to not only improve their grades, but to understand the topics better as a whole.

Feel free to book a 'meet the tutor' session to get to know me a bit better and I look forward to meeting you :)

Anna

Subjects offered

SubjectLevelMy prices
Biology A Level £22 /hr
Maths A Level £22 /hr
Biology GCSE £20 /hr
Maths GCSE £20 /hr
Maths 13 Plus £20 /hr

Qualifications

QualificationLevelGrade
MathematicsA-LevelA*
Further MathematicsA-LevelA*
BiologyA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

03/12/2014

CRB/DBS Enhanced

No

Currently unavailable: for regular students

Ratings and reviews

4.8from 9 customer reviews

Cherri (Parent) April 17 2016

Kiera was very happy with the tuition given by Anna. She felt that Anna helped her with the areas she was struggling with. She liked her manner and the way she taught her.

John (Parent) March 21 2015

Excellent tutorial. 5 star teacher

John (Student) March 20 2015

Excellent Tutorial

John (Student) March 21 2015

Excellent tutorial
See all reviews

Questions Anna has answered

What is a stationary point and how do I find where they occur and distinguish between them?

A stationary point is simply a point on a graph where the derivative=0. Ie, the rate of change of the curveat this point is 0 and therefore it is neither increasing or decreasingat this point.  There are three types you need to know about: 1) A maximum: Here the derivative =0 and the second d...

A stationary point is simply a point on a graph where the derivative=0. Ie, the rate of change of the curve at this point is 0 and therefore it is neither increasing or decreasing at this point

There are three types you need to know about:

1) A maximum: Here the derivative =0 and the second derivative <0.

2) A minimum: Here the derivative =0 and the second derivative >0

3) A point of inflection: Here the derivative and the second derivative =0

Note, the second derivative means the derivative of the first derivative!

General solution:

Suppose y=f(x)

and dy/dx=f'(x)

If at a point, say c, f'(c)=0 then there is a stationary point at this value of x.

Differentiate f'(x) to get the second derivative.

Plug in the value of c again and if the solution is..

0 - Point of inflection

Positive - Minimum turning point

Negative - Maximum turning point

Example

y = x3 - 6x2 + 9x - 4

Find any stationary points and determine their nature.

Solution 

dy/dx = 3x2- 12x + 9

At a stationary point, dy/dx=0

So 3x2- 12x + 9 = 0

3(x2- 4x + 3) = 0  

(x - 3)(x - 1) = 0

So stationary point at x = 3 and x = 1.

Now, to determine the nature of these..

f''(x) = 6x - 12

f''(3) = 18 - 12 = 6 therefore minimum turning point at x = 3

f''(1) = 6 - 12 = -6 therefore maximum turning point at x = 1

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2 years ago

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