Currently unavailable: for regular students
Degree: Economics with French (Bachelors) - Durham University
Having spent an Easter vacation giving one-to-one tuition to my younger brother and a number of his friends, I felt a desire to continue tutoring students, via MyTutorWeb. I have had the pleasure of teaching Maths and French in primary schools around Oxfordshire. This was an invaluable experience where I was able to gain a strong understanding of how to communicate with pupils in a learning environment.
The student will guide what we cover during the sessions. Whether a particular topic requires in-depth attention or simply a revision of some key points, I will teach the theory behind the concept before working through applied problems and examples. I believe this encourages independent thought while training the mind to spot precisely what is required to gain top marks in examinations. Through experience, I have acquired a range of teaching methods, which I will tailor to meet the individual needs of the student.
I am hugely passionate about Maths, French and History. French demands a high degree of logic, particularly when mastering grammar. In Mathematics, while logic is crucial, I believe an ability to think outside the box when tackling applied examination questions is a skill which I believe I can teach. In history, being able to structure essays and tackle source-based questions are both vital to all levels of history and are skills which, in my experience, are improved significantly through tutor guidance.
The subjects I have studied provide me with fundamental skills that I would take pleasure in passing on to fellow students. I hope to reach the point where a student, faced with an unseen problem, can approach it from different angles with confidence in their ability.
|Maths||A Level||£24 /hr|
|French||13 Plus||£22 /hr|
|History||13 Plus||£22 /hr|
|Maths||13 Plus||£22 /hr|
|-Personal Statements-||Mentoring||£24 /hr|
If y is a function of u, which itself is a function of x, then
dy/dx=(dy/du) x (du/dx)
Differentiate the outer function and multiply by the derivative of the inner function.
To illustrate this rule, look at the example below:
in which y=u10 and u=2x+3
The chain rule then gives
dy/dx=(dy/du) x (du/dx) = 10(2x+3)9(2) = 20(2x+3)9