Currently unavailable: for regular students
Degree: BSc Discrete Mathematics (Bachelors) - Warwick University
I am an undergraduate Discrete Mathematics student at The University of Warwick and have recently finished my first year there with first-class grades.
I am most passionate about mathematics and music because they require a mixture of both creativity and sound logic.
Regarding teaching experience, I taught piano lessons to a secondary school student and taught music to a school orchestra and choir during sixth form. These experiences enabled me to develop patience and clarity when teaching.
The tutoring sessions
I will ensure that you leave each session with a clear understanding of the topics that we have covered. This will be done by encouraging you to explain the lesson's concepts to me in your own words.
I believe in the power of engaging as many senses as possible in the learning experience, so I will use and recommend different modes of learning, including videos, audio clips and practical exercises.
I am able to share advice about the university application process for mathematics-related degrees, as I have recently been through this. Additionally, I am very happy to suggest ways in which you can practically apply mathematical and musical concepts in the real world.
I look forward to hearing from you soon!
|Maths||A Level||£20 /hr|
|Music||A Level||£20 /hr|
Martina (Parent) August 16 2016
Robin (Parent) February 23 2016
Trudy (Parent) February 19 2016
Robin (Parent) April 26 2016
This is an example of implicit differentiation with respect to x.
The technique for differentiating such an equation is as follows:
1. Differentiate each term in x with respect to x.
2. For each term in y, differentiate with respect to y, and multiply the result by dy/dx.
3. Rearrange the resulting equation, to make dy/dx the subject of the formula.
Let equation (x^2) + 2y = 4(y^3) + lnx be called (*).
Differentiating (*) with respect to x, then rearranging, according to the three rules above, gives:
2x + 2(dy/dx) = [12(y^2)](dy/dx) + (1/x) =>
[2 - 12(y^2)](dy/dx) = (1/x) - 2x =>
2[1 - 6(y^2)](dy/dx) = [1 - 2(x^2)]/x =>
dy/dx = [1 - 2(x^2)]/(2x[1 - 6(y^2)]).