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Degree: Physics with Medical Physics (Bachelors) - Cardiff University
Personally, one of my favourite feelings comes from looking back at a set of equations or terminology that used to look horribly complicated, and actually being able to make sense of them. Through tutoring, I hope to extend this satisfaction to others.
The best thing a teacher can do is to show people how to teach themselves, offering guidance to the solution, rather than just the answer. If I can make maths and science as appealing to your children as it was to me, then I've done my job. As complex and dry as physics can sound, at the heart of it is problem solving, from programming to setting up practical experiments.
Physics at university, along with teaching piano after passing grade 8, and giving back to my karate community by teaching youngsters, has given me a wide variety of skills that can help with tutoring.
I like to solve problems, and while I can't say I enjoyed it all of the time, doing well in the sciences (maths, biology, chemistry and physics) at both GCSE and A-level, gave me a renewed appreciation for them, leading to my study of physics.
|Chemistry||A Level||£20 /hr|
Over 1 second, electrons with drift velocity V travel through a wire of cross sectional area A. Distance Vt (t = 1) multiplied by area A gives a volume AV. This volume multiplied by the electron density of the material n, gives the number of electrons in volume V, nAV. The charge in the volume of material is found by multiplying the number of electrons by the elementary charge e, nAVe. This is the amount of charge passing through the wire every second, or current I. Therefore, I = nAVesee more
Maxwell's equations in free space:
∇ . E = 0
∇ x E = -∂B/∂t
∇ . B = 0
∇ x B = (1/c2)(∂E/∂t)
The wave equation:
∇2U = (1/c2)(∂2U/∂t2)
If we take the curl of ∇ x E, we get ∇ x(∇ x E) = -(∂/∂t)∇ x B
Using the vector formula a×(b×c) = b(a· c)−c(a·b), we can expand the left hand side to: ∇(∇ . E) - E(∇.∇)
Since ∇.E = 0, this becomes -∇2E = -(∂/∂t)∇ x B
As ∇ x B = (1/c2)(∂E/∂t), we have -∇2E = -(∂/∂t)(1/c2)(∂E/∂t)
Thus, ∇2E = (1/c2)(∂2E/∂t2) which shows that Maxwell's equations satisfy the wave equation. A similar process can be applied to Bsee more