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About me

Who am I?

Hey! I'm Neha, a third-year medical student at the University of Birmingham. I have loved maths and sciences all my life and I am looking to tutor students in these subjects to share my passion and help them to achieve the best grade they can! Having been a subject mentor at college, I have experience in tutoring students and really enjoy imparting my knowledge to others. 

The Tutorials

Our interactive sessions will involve teaching on the topics you'd like support with, tailored to your exam board/syllabus, so that you have the foundational understanding required to approach exam questions on the subject. This will be followed by revision, exam-style questions and anything else you'd like in order to help you feel more confident with tackling the topic in future. I hope that you will find our sessions enjoyable and I will do everything I can to ensure you take something new away from the tutorial! My aim is to work with you and push you so that you can excel further in the subjects covered in our sessions.

What next?

I hope that you are interested in having a tutorial with me and I am happy to answer any questions you may have (just send me a 'WebMail' or book a 'Meet the Tutor Session'! - please let me know what you'd like to cover so that I can prepare for the tutorial in advance). I look forward to tutoring you! 

Subjects offered

SubjectLevelMy prices
Biology A Level £24 /hr
Biology GCSE £22 /hr
Maths GCSE £22 /hr

Qualifications

QualificationLevelGrade
BiologyA-LevelA*
ChemistryA-LevelA*
MathsA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

10/05/2012

Ratings and reviews

5from 8 customer reviews

Zahida (Parent) October 19 2016

Neha is a brilliant tutor I would greatly recommend her to anyone who is struggling with biology. I have only had my first tutorial yet but I feel very confident as the techniques Neha has used to teach me has made me very confident about biology overall

Jacinda (Parent) August 4 2016

Very helpful and friendly tutor, explains concept clearly and always prepares the session before hand. Thank you Neha.

Sheila (Parent) June 2 2015

Fantastic help. I was struggling with three questions and I knew, just my luck, these type of questions will be on the text. Neha was able to give me a last minute late evening lesson, and explained thoroughly and clearly what I needed to do. I had a test the next day and got 43 out of 45. Yeh!!! Thanks Neha! Austin

Kimy (Parent) November 18 2016

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Questions Neha has answered

How do I draw a straight line graph given a y=mx+c equation by the table method?

The y=mx+c equation is for a straight line (also known as 'linear') graph. The 'y' is representative of the y-value, 'm' represents the gradient (how steep the graph is) and 'c' represents the y-intercept (where the graph cuts the y-axis). To do this by the table method, lets take the followi...

The y=mx+c equation is for a straight line (also known as 'linear') graph.

The 'y' is representative of the y-value, 'm' represents the gradient (how steep the graph is) and 'c' represents the y-intercept (where the graph cuts the y-axis).

To do this by the table method, lets take the following example:

Qu: Draw the graph of y=3x+4 for values of x between -3 and 3

We would draw a table as follows:

x:    -3   -2   -1   0   1   2    3      

3x:  -9   -6   -3   0   3   6    9

+4: +4  +4  +4  +4 +4  +4  +4

y:    -5   -2   -1   4   7  10   13

The first thing you do is write down the x-values for which the graph needs to be drawn (as specified in the qu, these are between -3 and 3)

You then put the 'mx' part of the equation in the next row. In our equation, m has the value of 3, so you write 3x (which algrebraically means 3 multiplied by x). Therefore, you multiple each x-value by 3, e.g -3x3=-9, -2x3=-6 etc. and write these values in.

You then put the +c part of the equation in the row below. In our equation, c has the value of 4, so you put +4 along the whole row. 

You then work out the y-value by adding the 2 rows above. Eg. For the value of x=-3, y=-9+4 which is equal to -5. Therefore, when x is -3, y is -5 - the coordinates would be (-3, -5). You do this for every value, which will give you a series of coordinates. 

You can then plot these coordinates on a graph and join them up to form your line graph!

 
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2 years ago

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