PremiumNeha C. A Level Biology tutor, GCSE Maths tutor, GCSE Biology tutor
£24 - £26 /hr

Neha C.

Degree: Medicine (Bachelors) - Birmingham University

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About me

Who am I?

Hey! I'm Neha, a final year medical student at the University of Birmingham. I have loved maths and sciences all my life and I am looking to tutor students in these subjects to share my passion and help them to achieve the best grade they can! Having been a subject mentor at college, I have experience in tutoring students and really enjoy imparting my knowledge to others. 

About my sessions

The Tutorials

Our interactive sessions will involve teaching on the topics you'd like support with, tailored to your exam board/syllabus, so that you have the foundational understanding required to approach exam questions on the subject. This will be followed by revision, exam-style questions and anything else you'd like in order to help you feel more confident with tackling the topic in future. I hope that you will find our sessions enjoyable and I will do everything I can to ensure you take something new away from the tutorial! My aim is to work with you and push you so that you can excel further in the subjects covered in our sessions.

What next?

I hope that you are interested in having a tutorial with me and I am happy to answer any questions you may have (just send me a 'WebMail' or book a 'Meet the Tutor Session'! - please let me know what you'd like to cover so that I can prepare for the tutorial in advance). I look forward to tutoring you! 

Subjects offered

SubjectQualificationPrices
Biology A Level £26 /hr
Biology GCSE £24 /hr
Maths GCSE £24 /hr
Biology IB £26 /hr
Maths 13 Plus £24 /hr
Maths 11 Plus £24 /hr

Qualifications

SubjectQualificationLevelGrade
BiologyA-levelA2A*
ChemistryA-levelA2A*
MathsA-levelA2A
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

10/05/2012

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Please get in touch for more detailed availability

Ratings and reviews

5from 26 customer reviews

Zahida (Parent)

Neha is a A*****tutor and I would highly reccommend her to anyone who is struggling in graspiong scientific concepts

Kimy (Parent)

Neha helped increase my biology by one grad. She has been very helpful throughout the year and is generous with her time

Fouad (Parent) July 31 2017

She is a GREAT help to my daughter

Kimy (Parent) June 15 2017

Neha has been very helpful in preparing me for my a level exams and improving my understanding of different concepts by explaining topics in a way that is both simple and enjoyable. I would definitely recommend her!
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Questions Neha has answered

How do I draw a straight line graph given a y=mx+c equation by the table method?

The y=mx+c equation is for a straight line (also known as 'linear') graph. The 'y' is representative of the y-value, 'm' represents the gradient (how steep the graph is) and 'c' represents the y-intercept (where the graph cuts the y-axis). To do this by the table method, lets take the followi...

The y=mx+c equation is for a straight line (also known as 'linear') graph.

The 'y' is representative of the y-value, 'm' represents the gradient (how steep the graph is) and 'c' represents the y-intercept (where the graph cuts the y-axis).

To do this by the table method, lets take the following example:

Qu: Draw the graph of y=3x+4 for values of x between -3 and 3

We would draw a table as follows:

x:    -3   -2   -1   0   1   2    3      

3x:  -9   -6   -3   0   3   6    9

+4: +4  +4  +4  +4 +4  +4  +4

y:    -5   -2   -1   4   7  10   13

The first thing you do is write down the x-values for which the graph needs to be drawn (as specified in the qu, these are between -3 and 3)

You then put the 'mx' part of the equation in the next row. In our equation, m has the value of 3, so you write 3x (which algrebraically means 3 multiplied by x). Therefore, you multiple each x-value by 3, e.g -3x3=-9, -2x3=-6 etc. and write these values in.

You then put the +c part of the equation in the row below. In our equation, c has the value of 4, so you put +4 along the whole row. 

You then work out the y-value by adding the 2 rows above. Eg. For the value of x=-3, y=-9+4 which is equal to -5. Therefore, when x is -3, y is -5 - the coordinates would be (-3, -5). You do this for every value, which will give you a series of coordinates. 

You can then plot these coordinates on a graph and join them up to form your line graph!

 
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3 years ago

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