Currently unavailable: until 15/03/2016

Degree: Maths (Masters) - York University

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Hi, I'm Chris. I'm a second year Maths student at the University of York, and I really look forward to tutoring anyone who needs some help with their maths! I love the subject, especially pure maths, and always try to learn the concepts behind ideas, so as to not only understand it better myself, but also to help others on it.

I studied GCSE and A-Level maths, getting an A* in both, as well as A-Level further maths, getting an A. More specifically, I studied the Core 1, Core 2, Core 3, Core 4, Mechanics 1, Mechanics 2, Statistics 1, Statistics 2, Further Pure 1, Further Pure 2, Further Pure 3, and Further Pure 4 modules from the AQA exam board, in addition to a high first in my first year. While studying in my A2 year, I tutored an AS student, helping to understand the underlying ideas behind the more complicated concepts involved.

If you have anything you want to ask me, feel free to send me a message to me through my tutor web, or book a "Meet the tutor" session.

I look forward to meeting you!

#### Subjects offered

SubjectQualificationPrices
Further Mathematics A Level £20 /hr
Maths A Level £20 /hr
Maths GCSE £18 /hr

#### Qualifications

MathsA-levelA2A*
Further MathsA-levelA2A
 CRB/DBS Standard No CRB/DBS Enhanced No

### How do I integrate sin^2(x)?

First, remember the compound angle formula for cosine: cos(2x)=cos^2(x)-sin^2(x).  Now use the identity sin^2(x)+cos^2(x)=1 to give: cos(2x)=(1-sin^2(x))-sin^2(x)=1-2sin^2(x) Rearranging this so we have sin^2(x)=1/2(1-cos(2x)) Replace this with the original integration and use the chain rule ...

First, remember the compound angle formula for cosine:

cos(2x)=cos^2(x)-sin^2(x).  Now use the identity sin^2(x)+cos^2(x)=1 to give:

cos(2x)=(1-sin^2(x))-sin^2(x)=1-2sin^2(x)

Rearranging this so we have sin^2(x)=1/2(1-cos(2x))

Replace this with the original integration and use the chain rule to get:

1/2(x-1/2sin(2x))+c

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3 years ago

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