Currently unavailable: for new students
Degree: Natural Sciences (Bachelors) - Cambridge University
My name is James Alexander, and I am here to help you with anything science related. At A level, I studied Maths, Further Maths, Chemistry and Physics, achieving A*s in all of them. I study Natural Sciences at Cambridge now, which has taught me some incredibly useful information about sciences and that I can now pass down to you.
I completely believe that, under the right circumstances, being taught can be fun for everyone. Learning doesn't have to be 'sat at the back of the class twiddling your thumbs'. By looking for a tutor, you have taken your first step in learning to love learning, and I can definitely help you on your way to achieving your highest potential and getting the grades neccesary to do whatever you want in life.
I can also help out with any personal statements and oxbridge applications; I have been through rigourous interview training myself and have helped countless others wirth personal statement writing. I know what the universities are looking for and can increase your chances greatly. I also know a lot about the oxbridge process and am able to give practice interviews and help give lessons on how to come across well in an interview situation.
I am willing to help out with Maths, Chemistry or Physics of any secondary school level, GCSE or A-Level. Best of luck with your studies, and I hope that I am able to help you out!
|Chemistry||A Level||£22 /hr|
|Maths||A Level||£22 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
Amjad (Parent) April 1 2015
Amjad (Parent) March 22 2015
Amjad (Parent) March 10 2015
The chain rule is incredibly useful when differentiating compositions of funcions.
Until now you have really only met dy/dx as your derivative. By imagining dy/dx as a fraction, you can transform it into something using another parameter, for example t.
For example, just how 1/2 x 2/3 = 2/6 (multiply numerater, multiply denominator), dy/dx x dt/dy = dydt/dxdy, and the 'dy' values would cancel, giving dt/dx. This is only for this level of mathematics however, as in reality, you can't treat dy/dx as a fraction!