Hi, i'm Jenny!
I first started tutoring Maths when I was 17 with the peer mentoring scheme helping other students in my year and the year below with a-level maths. I loved being able to help people with a subject I really love and understand and improving there knowledge and enthusiam for Maths.
I also helped my younger sister with gcse maths and now a-level maths which she will be sitting in the summer, this allows me to practice different teaching methods and see which ones work most effectively.
By keeping student interested I use a lot of different examples, and not only teach them the exact topic they wish to learn but topics related to the main topic so that it improves there overall understanding.
Tutoring gives me a real sense of achievement especially seeing the students improving and getting the grades they deserve.
Hope I can help soon, thank you!
|Maths||A Level||£20 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
If we have the 2 lines
line 1 - 3y=4x+2 and line 2 - 6y=7x+3
Firstly we would look for when the y's or x's are multiples of each other in this case the y's are multiples of each other as 3 is a multiple of 6.
Therefore we would times line 1 by 2 to become 6y=8x+4 -line 3
we then use line 2 and 3 as simultaneous equations to try and only have one variable in this case x.
line 2 - line 3 will give us 0=-x-1, so rearranging and moving x to the other side of the equation x=-1, then we put this back into any of the 3 lines to find out what y equals at this point.
So using line 1.. 3y= 4(-1)+2 so 3y=-2 so y=-2/3
so the lines 1 and 2 intersect at the point (-1,-2/3)see more