Jennifer L. GCSE Maths tutor, A Level Maths tutor, GCSE Chemistry tutor

Jennifer L.

£18 - £20 /hr

Currently unavailable:

Studying: Mathematics with Finance (Bachelors) - Exeter University

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About me

Hi, i'm Jenny!

I first started tutoring Maths when I was 17 with the peer mentoring scheme helping other students in my year and the year below with a-level maths. I loved being able to help people with a subject I really love and understand and improving there knowledge and enthusiam for Maths.

I also helped my younger sister with gcse maths and now a-level maths which she will be sitting in the summer, this allows me to practice different teaching methods and see which ones work most effectively.

By keeping student interested I use a lot of different examples, and not only teach them the exact topic they wish to learn but topics related to the main topic so that it improves there overall understanding.

Tutoring gives me a real sense of achievement especially seeing the students improving and getting the grades they deserve.

Hope I can help soon, thank you!

Hi, i'm Jenny!

I first started tutoring Maths when I was 17 with the peer mentoring scheme helping other students in my year and the year below with a-level maths. I loved being able to help people with a subject I really love and understand and improving there knowledge and enthusiam for Maths.

I also helped my younger sister with gcse maths and now a-level maths which she will be sitting in the summer, this allows me to practice different teaching methods and see which ones work most effectively.

By keeping student interested I use a lot of different examples, and not only teach them the exact topic they wish to learn but topics related to the main topic so that it improves there overall understanding.

Tutoring gives me a real sense of achievement especially seeing the students improving and getting the grades they deserve.

Hope I can help soon, thank you!

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Qualifications

SubjectQualificationGrade
MathematicsA-level (A2)A*
Further MathematicsA-level (A2)A
ChemistryA-level (A2)A

General Availability

Before 12pm12pm - 5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
MathsA Level£20 /hr
ChemistryGCSE£18 /hr
MathsGCSE£18 /hr

Questions Jennifer has answered

How to add fractions

 

A: Firstly to add fractions the denominators have to be the same.

For example, 3/7 + 2/3

firstly you need to work out the lcm of 7 and 3, in this case it is 21.

So each fraction needs to be put into the form a/21 + b/21

For the fraction 3/7, you are timsing the 7 by 3  to get 21, so you also need to times the numerator by leaving you with 9/21 which = 3/7 

Then starting with 2/3, to get a denominator of 21, you need to times 3 by 7, so you also need to times the numerator by leaving you with 14/21 which =2/3

Finally to add the 2 fractions 9/21 + 14/21 = 23/21

Other examples for you to try..

1) 3/5 + 2/3

2) 3/5 + 6/20

 

 

A: Firstly to add fractions the denominators have to be the same.

For example, 3/7 + 2/3

firstly you need to work out the lcm of 7 and 3, in this case it is 21.

So each fraction needs to be put into the form a/21 + b/21

For the fraction 3/7, you are timsing the 7 by 3  to get 21, so you also need to times the numerator by leaving you with 9/21 which = 3/7 

Then starting with 2/3, to get a denominator of 21, you need to times 3 by 7, so you also need to times the numerator by leaving you with 14/21 which =2/3

Finally to add the 2 fractions 9/21 + 14/21 = 23/21

Other examples for you to try..

1) 3/5 + 2/3

2) 3/5 + 6/20

 

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3 years ago

682 views

How to find out where 2 lines cross/simultaneous equations

If we have the 2 lines

line 1 - 3y=4x+2 and line 2 - 6y=7x+3

Firstly we would look for when the y's or x's are multiples of each other in this case the y's are multiples of each other as 3 is a multiple of 6.

Therefore we would times line 1 by 2 to become 6y=8x+4 -line 3

we then use line 2 and 3 as simultaneous equations to try and only have one variable in this case x.

line 2 - line 3 will give us     0=-x-1, so rearranging and moving x to the other side of the equation x=-1, then we put this back into any of the 3 lines to find out what y equals at this point.

So using line 1.. 3y= 4(-1)+2 so 3y=-2 so y=-2/3

so the lines 1 and 2 intersect at the point (-1,-2/3)

If we have the 2 lines

line 1 - 3y=4x+2 and line 2 - 6y=7x+3

Firstly we would look for when the y's or x's are multiples of each other in this case the y's are multiples of each other as 3 is a multiple of 6.

Therefore we would times line 1 by 2 to become 6y=8x+4 -line 3

we then use line 2 and 3 as simultaneous equations to try and only have one variable in this case x.

line 2 - line 3 will give us     0=-x-1, so rearranging and moving x to the other side of the equation x=-1, then we put this back into any of the 3 lines to find out what y equals at this point.

So using line 1.. 3y= 4(-1)+2 so 3y=-2 so y=-2/3

so the lines 1 and 2 intersect at the point (-1,-2/3)

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3 years ago

784 views

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