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About me

At AS, I was extremely disappointed to achieve an E grade in maths. With little external support and belief in my abilities, I set about improving this grade by finding techniques to learning that suited me. This occasionally flew in the face of traditional learning styles, but I ended up achieving an A* in maths, achieving 97% of the available UMS marks across AS & A2. My explanatory skills have been widely celebrated by my tutees, peers (over the course of my secondary and undergraduate education), and my professors - recently scoring 93% on an assessment of my ability to communicate undergraduate level topics.

About my sessions

While mentoring students in learning strategies as individuals is not formally the aim of my tutorials, I hope to help passively establish the tools required to independently approach problems in novel ways, allowing each student to find the techniques in problem-solving for Maths, Physics and Chemistry which suit them. I request that all tutees send me an email at least 18 hours prior to our tutorials on the given topic to cover, in order that I can tailor information to the needs of individual exam boards/syllabuses.

Subjects offered

SubjectLevelMy prices
Further Mathematics A Level £36 /hr
Maths A Level £36 /hr
Physics A Level £36 /hr
Chemistry GCSE £36 /hr
Further Mathematics GCSE £36 /hr
Maths GCSE £36 /hr
Physics GCSE £36 /hr
Science GCSE £36 /hr

Qualifications

QualificationLevelGrade
PhysicsA-LevelA*
MathematicsA-LevelA*
ChemistryA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

General Availability

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Please get in touch for more detailed availability

Ratings and reviews

4.9from 62 customer reviews

Marion (Parent) March 6 2017

he is good and helpful

Marion (Parent) February 8 2017

I am extremely glad that we found such a great tutor. My son struggles with some elements of learning; Jacan has helped him to stay on track to get his GCSEs despite missing the majority of his lessons at school due to illness. My son thinks Jacan is a really good tutor.

Aziz (Parent) May 29 2016

Jacan is very perceptive and inspirational.

Aziz (Parent) May 22 2016

Jacan thought my son for the first time. His feedback to me was very useful.
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Questions Jacan has answered

How do I integrate ln(x)?

There is a subtle, but very neat trick to this when applying the rules of integration by parts. If we take ∫ln(x)dx = ∫1*ln(x)dx, and then let our term to be differentiated, u = ln(x), and our term to be integrated, dv/dx = 1, then it follows that:   du/dx = x⁻¹, v = x   and from the integ...

There is a subtle, but very neat trick to this when applying the rules of integration by parts.

If we take ∫ln(x)dx = ∫1*ln(x)dx, and then let our term to be differentiated, u = ln(x), and our term to be integrated, dv/dx = 1, then it follows that:

 

du/dx = x⁻¹, v = x

 

and from the integration by parts formula:

∫u * (dv/dx) dx = uv - ∫v * (du/dx) dx

 

∴ ∫ln(x)dx = xln(x) - ∫(x⁻¹ * x)dx (+ constant)

∫ln(x)dx = xln(x) - ∫dx (+ constant)

Hence, our results turns out to be:

∫ln(x)dx = xln(x) - x + c

 

NB. While our trick here gives us a very straightforward solution to an integration which could have been very laborious via other methods, integration by parts tends to be a last resort, as more, seemingly contrived steps are required. One should generally try integration by substitution, for non-standard integrations, first when unsure of which method to use, as the steps to a result are often far simpler and quicker.

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2 years ago

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