Jack T.

Jack T.

£18 - £20 /hr

MPHYS Physics with Astrophysics (Integrated Masters) - Exeter University

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About me

        I am a 2nd year student at the University of Exeter studying Physics with Astrophysics. I’ve always enjoyed physics both for its problem solving aspect and for its ability to explain the world around us.

               I know how stressful GCSEs and A-Levels can be, especially in subjects like maths and physics that can seem impossibly confusing at times. I hope to be able to alleviate some of that stress as I have done for friends and family that have struggled in these subjects.

        I am a 2nd year student at the University of Exeter studying Physics with Astrophysics. I’ve always enjoyed physics both for its problem solving aspect and for its ability to explain the world around us.

               I know how stressful GCSEs and A-Levels can be, especially in subjects like maths and physics that can seem impossibly confusing at times. I hope to be able to alleviate some of that stress as I have done for friends and family that have struggled in these subjects.

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About my sessions

        Everybody learns differently and everyone will struggle over different concepts, so I try to tailor my sessions to each individual student to best meet their needs. This means that my sessions are very interactive with the topics covered in each session generally being chosen by the student.

               I also try to use as many past paper questions as possible so that the student is familiar with how the questions are written and gains a better understanding of what the question wants from them.

        Everybody learns differently and everyone will struggle over different concepts, so I try to tailor my sessions to each individual student to best meet their needs. This means that my sessions are very interactive with the topics covered in each session generally being chosen by the student.

               I also try to use as many past paper questions as possible so that the student is familiar with how the questions are written and gains a better understanding of what the question wants from them.

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Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

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Qualifications

SubjectQualificationGrade
MathsA-level (A2)A
PhysicsA-level (A2)A
BiologyA-level (A2)B

General Availability

MonTueWedThuFriSatSun
Pre 12pm
12 - 5pm
After 5pm

Pre 12pm

12 - 5pm

After 5pm
Mon
Tue
Wed
Thu
Fri
Sat
Sun

Subjects offered

SubjectQualificationPrices
MathsA Level£20 /hr
PhysicsA Level£20 /hr
MathsGCSE£18 /hr
PhysicsGCSE£18 /hr

Questions Jack has answered

Find the area bounded by the curve x^3-3x^2+2x and the x-axis between x=0 and x=1.

To find the area under a curve that is bounded by the x-axis you simply need to integrate the equation of the curve between the limits, so for this equation we will integrate y=x3-3x2+2x with 1 as our upper limit and 0 as our lower limit. To integrate an expression you add 1 to the power and divide by the new power, so the integral of x3-3x2+2x is (1/4)x4-x3+x2. We then substitute x=1 and x=0 into the expression and subtract the resulting values from eachother. When x=1, (1/4)x4-3x3+x2=1/4 and when x=0, (1/4)x4-3x3+x2=0. (1/4)-0=1/4 and so that is our final answer to the question.To find the area under a curve that is bounded by the x-axis you simply need to integrate the equation of the curve between the limits, so for this equation we will integrate y=x3-3x2+2x with 1 as our upper limit and 0 as our lower limit. To integrate an expression you add 1 to the power and divide by the new power, so the integral of x3-3x2+2x is (1/4)x4-x3+x2. We then substitute x=1 and x=0 into the expression and subtract the resulting values from eachother. When x=1, (1/4)x4-3x3+x2=1/4 and when x=0, (1/4)x4-3x3+x2=0. (1/4)-0=1/4 and so that is our final answer to the question.

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10 months ago

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