About me
Hi, I’m Adil, and I am currently a first year Natural Scientist at Cambridge; I am planning to specialise in Chemical Engineering next year. My main target is to consolidate and enrich my tutees’ understanding in Sciences. This will be done according to their current level of understanding in the area and build up from their already existing knowledge. My main approaches will principally include exam techniques and “examiner-friendly” approaches to questions and problems.
I am very open-minded in terms of methods of teaching. I have helped students of different ages, at different academic levels. I am happy to carry the lesson at the pace desired by the student, yet making the lesson worth the time and money you have invested.
I have obtained outstanding results in my GCSEs and A-levels thanks to excellent organisation and substantial effort. The key to success at A-levels is not memorising a book, but understand key concepts and be extremely confident in applying them (almost methodically) to exam problems.
Hi, I’m Adil, and I am currently a first year Natural Scientist at Cambridge; I am planning to specialise in Chemical Engineering next year. My main target is to consolidate and enrich my tutees’ understanding in Sciences. This will be done according to their current level of understanding in the area and build up from their already existing knowledge. My main approaches will principally include exam techniques and “examiner-friendly” approaches to questions and problems.
I am very open-minded in terms of methods of teaching. I have helped students of different ages, at different academic levels. I am happy to carry the lesson at the pace desired by the student, yet making the lesson worth the time and money you have invested.
I have obtained outstanding results in my GCSEs and A-levels thanks to excellent organisation and substantial effort. The key to success at A-levels is not memorising a book, but understand key concepts and be extremely confident in applying them (almost methodically) to exam problems.
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Standard DBS Check
15/08/2014Ratings & Reviews
Anujin (Student)
October 1 2015
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Anujin (Student)
October 4 2015
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Mrs E (Parent from Milton Keynes)
October 4 2015
great
Anujin (Student)
October 2 2015
Thank you so much
Qualifications
Subjects offered
Questions Adil has answered
How to factorise any quadratic expression
Factorising quadratic equations
This method is used for the following factorable expression:
ax2+bx+c
Although this method is particularly useful with quadratic expressions with a≥2, it can be also used when a=1.
Given ax2+bx+c
Find SUM=b and PRODUCT=ac
Find two numbers p and q, such that p+q=SUM and pq=PRODUCT
The smallest number (without considering the sign), say in this case p, goes into the following bracket:
(ax+p)
The largest number (without considering the sign), say in this case, q, goes into the other bracket:
(x+q/a)
Hence the factorised form is:
(ax+p)(x+q/a)
Further algebra could be used to "tidy" the expression
Example
6x2 - 13x + 5
SUM = b = -13 and PRODUCT = ac = 6*5 = 30
So p = -3 and q = -10 , as SUM= -3 -10 = -13 and PRODUCT= (-3)*(-10) = 30
As p is the smallest number, this goes in (ax+p) = (6x-3)
And q being the largest, goes into (x+q/a) = (x-10/6)
Hence the factorised form is
(6x-3)(x-10/6)
or neater (2x-1)(3x-5)
Factorising quadratic equations
This method is used for the following factorable expression:
ax2+bx+c
Although this method is particularly useful with quadratic expressions with a≥2, it can be also used when a=1.
Given ax2+bx+c
Find SUM=b and PRODUCT=ac
Find two numbers p and q, such that p+q=SUM and pq=PRODUCT
The smallest number (without considering the sign), say in this case p, goes into the following bracket:
(ax+p)
The largest number (without considering the sign), say in this case, q, goes into the other bracket:
(x+q/a)
Hence the factorised form is:
(ax+p)(x+q/a)
Further algebra could be used to "tidy" the expression
Example
6x2 - 13x + 5
SUM = b = -13 and PRODUCT = ac = 6*5 = 30
So p = -3 and q = -10 , as SUM= -3 -10 = -13 and PRODUCT= (-3)*(-10) = 30
As p is the smallest number, this goes in (ax+p) = (6x-3)
And q being the largest, goes into (x+q/a) = (x-10/6)
Hence the factorised form is
(6x-3)(x-10/6)
or neater (2x-1)(3x-5)
