I’m not your typical maths tutor! I love keeping active and I train for 3 different sports, I speak English and Italian fluently and I can also speak intermediate-level French, German and Spanish. I will bring out the confidence and character out of your son or daughter, by keeping the tutorials fun and light-hearted. I can also Tutor maths in Spanish or Italian for those who struggle with English. I recently graduated from the University of Bristol where I got a first class masters in Mathematics. Now I am currently working on a start-up and tutoring part time. At A-Level I got A* - A* - A - A - A in Maths - Economics - Further Maths - Physics - Italian. I have been through so many A-level maths papers that I know what you need to learn and the best way to teach it!

I’m not your typical maths tutor! I love keeping active and I train for 3 different sports, I speak English and Italian fluently and I can also speak intermediate-level French, German and Spanish. I will bring out the confidence and character out of your son or daughter, by keeping the tutorials fun and light-hearted. I can also Tutor maths in Spanish or Italian for those who struggle with English. I recently graduated from the University of Bristol where I got a first class masters in Mathematics. Now I am currently working on a start-up and tutoring part time. At A-Level I got A* - A* - A - A - A in Maths - Economics - Further Maths - Physics - Italian. I have been through so many A-level maths papers that I know what you need to learn and the best way to teach it!

I can provide a rapid revision class in any maths module which will test your son or daughter in all the fundamentals and important techniques to make sure he/she is prepared for the exams coming up in January or June. I am available at short notice so send me a message.

I can provide a rapid revision class in any maths module which will test your son or daughter in all the fundamentals and important techniques to make sure he/she is prepared for the exams coming up in January or June. I am available at short notice so send me a message.

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5from 149 customer reviews

Alex (Student)

August 29 2017

Very helpful and helps me learn concepts I don't understand without rushing me. He always tries to make me find the answer so that I get a better understanding.

Ken (Parent from Beaconsfield)

August 18 2017

Una volta divertente. Che pecato non posso parlare meglio italiano!

Ken (Parent from Beaconsfield)

July 28 2017

Really helped my listening skills - even though I know that Giulio was speaking slowly!

Ken (Parent from Beaconsfield)

July 7 2017

Un buono conversazione!

Polynomial long division is how to divide long functions f(x), called the dividend, by another function g(x), called the divisor. Which could lead to having a remainder, if it doesn't divide perfectly.

Luckily there is one simple method to follow,

Let's divide f(x) = x^2+2x+5

by g(x) = x-2

First write it out like

____

g(x) | f(x)

__________

x-2 | x^2+2x+5

Now only look at the the first term in f(x), which is x^2, and our first term in g(x) which is x.

how many times does x go into x^2? The answer is x times thus we write x on top of our function, like this:

x

___________

x-2 | x^2+2x+5

Then multiply x^2 by our divisor x - 2 to get x^2-2x, and write it below the function like this:

x

____________

x-2 | x^2+2x+5

_____________

x^2 -2x

Now we simply find x^2+2x minus (x^2-2x) = 4x

So add the 4x on a new row below, but also don't forget to carry down the + 5 term from our dividend, thus it should now look like this.

x

__________

x-2 | x^2+2x+5

___________

x^2 -2x

___________

4x +5

Now it is as if we are dividing 4x + 5 by x - 2, so we ask the same question again, how many times does x go into 4x, the answer is 4 times, thus write + 4 at the top

x + 4

__________

x-2 | x^2+2x+5

___________

x^2 -2x

___________

4x +5

And then multiply 4 by x -2 and write it below, like this

x + 4

__________

x-2 | x^2+2x+5

___________

x^2 -2x

___________

4x +5

___________

4x - 8

Now find 4x+5 minus (4x -8) = 13 and write it below

x + 4

__________

x-2 | x^2+2x+5

___________

x^2 -2x

___________

4x +5

___________

4x - 8

___________

13

Since we can no longer divide we are left with the remainder which is is 13/(x-2)

Thus the solution is what we have at the top plus the remainder,

the solution is

x + 4 + 13/(x-2)

Polynomial long division is how to divide long functions f(x), called the dividend, by another function g(x), called the divisor. Which could lead to having a remainder, if it doesn't divide perfectly.

Luckily there is one simple method to follow,

Let's divide f(x) = x^2+2x+5

by g(x) = x-2

First write it out like

____

g(x) | f(x)

__________

x-2 | x^2+2x+5

Now only look at the the first term in f(x), which is x^2, and our first term in g(x) which is x.

how many times does x go into x^2? The answer is x times thus we write x on top of our function, like this:

x

___________

x-2 | x^2+2x+5

Then multiply x^2 by our divisor x - 2 to get x^2-2x, and write it below the function like this:

x

____________

x-2 | x^2+2x+5

_____________

x^2 -2x

Now we simply find x^2+2x minus (x^2-2x) = 4x

So add the 4x on a new row below, but also don't forget to carry down the + 5 term from our dividend, thus it should now look like this.

x

__________

x-2 | x^2+2x+5

___________

x^2 -2x

___________

4x +5

Now it is as if we are dividing 4x + 5 by x - 2, so we ask the same question again, how many times does x go into 4x, the answer is 4 times, thus write + 4 at the top

x + 4

__________

x-2 | x^2+2x+5

___________

x^2 -2x

___________

4x +5

And then multiply 4 by x -2 and write it below, like this

x + 4

__________

x-2 | x^2+2x+5

___________

x^2 -2x

___________

4x +5

___________

4x - 8

Now find 4x+5 minus (4x -8) = 13 and write it below

x + 4

__________

x-2 | x^2+2x+5

___________

x^2 -2x

___________

4x +5

___________

4x - 8

___________

13

Since we can no longer divide we are left with the remainder which is is 13/(x-2)

Thus the solution is what we have at the top plus the remainder,

the solution is

x + 4 + 13/(x-2)