Giulio P. GCSE Maths tutor, A Level Maths tutor, A Level Economics tu...

Giulio P.

£36 /hr

Studying: Mathematics (Masters) - Bristol University

5.0
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120 reviews| 271 completed tutorials

Contact Giulio

About me

I’m not your typical maths tutor! I love keeping active and I train for 3 different sports, I speak English and Italian fluently and I can also speak intermediate-level French, German and Spanish. I will bring out the confidence and character out of your son or daughter, by keeping the tutorials fun and light-hearted. I can also Tutor maths in Spanish or Italian for those who struggle with English. I recently graduated from the University of Bristol where I got a first class masters in Mathematics. Now I am currently working on a start-up and tutoring part time. At A-Level I got A* - A* - A - A - A in Maths - Economics - Further Maths - Physics - Italian. I have been through so many A-level maths papers that I know what you need to learn and the best way to teach it! I’m not your typical maths tutor! I love keeping active and I train for 3 different sports, I speak English and Italian fluently and I can also speak intermediate-level French, German and Spanish. I will bring out the confidence and character out of your son or daughter, by keeping the tutorials fun and light-hearted. I can also Tutor maths in Spanish or Italian for those who struggle with English. I recently graduated from the University of Bristol where I got a first class masters in Mathematics. Now I am currently working on a start-up and tutoring part time. At A-Level I got A* - A* - A - A - A in Maths - Economics - Further Maths - Physics - Italian. I have been through so many A-level maths papers that I know what you need to learn and the best way to teach it!

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About my sessions

It's Exam Time! I can provide a rapid revision class in any maths module which will test your son or daughter in all the fundamentals and important techniques to make sure he/she is prepared for the exams coming up in a few weeks time. I am available at short notice so send me a message.It's Exam Time! I can provide a rapid revision class in any maths module which will test your son or daughter in all the fundamentals and important techniques to make sure he/she is prepared for the exams coming up in a few weeks time. I am available at short notice so send me a message.

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Ratings & Reviews

5from 120 customer reviews
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Alex (Student)

August 29 2017

Very helpful and helps me learn concepts I don't understand without rushing me. He always tries to make me find the answer so that I get a better understanding.

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Ken (Parent)

August 18 2017

Una volta divertente. Che pecato non posso parlare meglio italiano!

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Ken (Parent)

July 28 2017

Really helped my listening skills - even though I know that Giulio was speaking slowly!

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Ken (Parent)

July 7 2017

Un buono conversazione!

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Qualifications

SubjectQualificationGrade
MathematicsA-level (A2)A*
EconomicsA-level (A2)A*
Further MathematicsA-level (A2)A
ItalianA-level (A2)A
PhysicsA-level (A2)A

General Availability

Before 12pm12pm - 5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
EconomicsA Level£36 /hr
Further Mathematics A Level£36 /hr
ItalianA Level£36 /hr
MathsA Level£36 /hr
ItalianGCSE£36 /hr
MathsGCSE£36 /hr
PhysicsGCSE£36 /hr

Questions Giulio has answered

Polynomial long division, how do I do it?

Polynomial long division is how to divide long functions f(x), called the dividend, by another function g(x), called the divisor. Which could lead to having a remainder, if it doesn't divide perfectly. 

Luckily there is one simple method to follow, 
 
Let's divide f(x) = x^2+2x+5 
by g(x) = x-2 
                                    
First write it out like 
        ____
g(x) | f(x) 
        __________
x-2 |  x^2+2x+5
 
 Now only look at the the first term in f(x), which is x^2, and our first term in g(x) which is x. 
how many times does x go into x^2? The answer is x times thus we write x on top of our function, like this:
 
          x
        ___________
 x-2 |  x^2+2x+5
 
Then multiply x^2 by our divisor x - 2 to get x^2-2x, and write it below the function like this:
 
          x
        ____________
 x-2 |  x^2+2x+5
        _____________
          x^2 -2x
 
Now we simply find x^2+2x minus (x^2-2x) = 4x
 
So add the 4x on a new row below, but also don't forget to carry down the + 5 term from our dividend, thus it should now look like this.
 
          x
        __________
 x-2 |  x^2+2x+5
        ___________
         x^2 -2x
        ___________
                 4x +5
 
Now it is as if we are dividing 4x + 5 by x - 2, so we ask the same question again, how many times does x go into 4x, the answer is 4 times, thus write + 4 at the top 
 
          x + 4
        __________
 x-2 |  x^2+2x+5
        ___________
         x^2 -2x
        ___________
                 4x +5
        
 
And then multiply 4 by x -2 and write it below, like this 
 
           x + 4
        __________
 x-2 |  x^2+2x+5
        ___________
         x^2 -2x
        ___________
                 4x +5
        ___________
                 4x - 8
 
Now find 4x+5  minus (4x -8) = 13 and write it below
 
           x + 4
        __________
 x-2 |  x^2+2x+5
        ___________
         x^2 -2x
        ___________
                 4x +5
        ___________
                 4x - 8
        ___________
                      13
 
Since we can no longer divide we are left with the remainder which is is 13/(x-2) 
 
Thus the solution is what we have at the top plus the remainder, 
the solution is
x + 4 + 13/(x-2) 
 
 
 

Polynomial long division is how to divide long functions f(x), called the dividend, by another function g(x), called the divisor. Which could lead to having a remainder, if it doesn't divide perfectly. 

Luckily there is one simple method to follow, 
 
Let's divide f(x) = x^2+2x+5 
by g(x) = x-2 
                                    
First write it out like 
        ____
g(x) | f(x) 
        __________
x-2 |  x^2+2x+5
 
 Now only look at the the first term in f(x), which is x^2, and our first term in g(x) which is x. 
how many times does x go into x^2? The answer is x times thus we write x on top of our function, like this:
 
          x
        ___________
 x-2 |  x^2+2x+5
 
Then multiply x^2 by our divisor x - 2 to get x^2-2x, and write it below the function like this:
 
          x
        ____________
 x-2 |  x^2+2x+5
        _____________
          x^2 -2x
 
Now we simply find x^2+2x minus (x^2-2x) = 4x
 
So add the 4x on a new row below, but also don't forget to carry down the + 5 term from our dividend, thus it should now look like this.
 
          x
        __________
 x-2 |  x^2+2x+5
        ___________
         x^2 -2x
        ___________
                 4x +5
 
Now it is as if we are dividing 4x + 5 by x - 2, so we ask the same question again, how many times does x go into 4x, the answer is 4 times, thus write + 4 at the top 
 
          x + 4
        __________
 x-2 |  x^2+2x+5
        ___________
         x^2 -2x
        ___________
                 4x +5
        
 
And then multiply 4 by x -2 and write it below, like this 
 
           x + 4
        __________
 x-2 |  x^2+2x+5
        ___________
         x^2 -2x
        ___________
                 4x +5
        ___________
                 4x - 8
 
Now find 4x+5  minus (4x -8) = 13 and write it below
 
           x + 4
        __________
 x-2 |  x^2+2x+5
        ___________
         x^2 -2x
        ___________
                 4x +5
        ___________
                 4x - 8
        ___________
                      13
 
Since we can no longer divide we are left with the remainder which is is 13/(x-2) 
 
Thus the solution is what we have at the top plus the remainder, 
the solution is
x + 4 + 13/(x-2) 
 
 
 

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3 years ago

1052 views

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