Jonathan R. GCSE Maths tutor, A Level Maths tutor

Jonathan R.

Currently unavailable: until 20/10/2016

Degree: Mechanical Engineering (Bachelors) - Warwick University

MyTutor guarantee

Contact Jonathan

About me

I am an engineering student at the University of Warwick. Maths has always been a passion of mine and I hope that my enthusiasm will allow you to get the most out of my tutorials.

I am a very friendly and understanding person. At primary school I was noted as a gifted and talented Maths student.

During the sessions I will focus on areas that you want to cover. First I will teach the concept until you have a strong understanding, before moving on to some exam style questions.

Maths is a great subject so I am sure you will find my tutorials fun but I will also do my best to make the sessions enjoyable.

I look forward to meeting you!

Subjects offered

SubjectQualificationPrices
Maths A Level £20 /hr
Maths GCSE £18 /hr

Qualifications

SubjectQualificationLevelGrade
MathsA-levelA2A*
Further MathsA-levelA2B
PhysicsA-levelA2B
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

General Availability

Currently unavailable: until

20/10/2016

Weeks availability
MonTueWedThuFriSatSun
Weeks availability
Before 12pm12pm - 5pmAfter 5pm
MONDAYMONDAY
TUESDAYTUESDAY
WEDNESDAYWEDNESDAY
THURSDAYTHURSDAY
FRIDAYFRIDAY
SATURDAYSATURDAY
SUNDAYSUNDAY

Please get in touch for more detailed availability

Questions Jonathan has answered

How can I find the area under the graph of y = f(x) between x = a and x = b?

You can find the area under this graph by evaluating the definite integral of y = f(x) with respect to x between x = a and x = b Please note: An area below the x-axis has a negative value Example: Find the area under the graph of y = x^2 between x = 3 and x = 6   Step 1: Integrate x^2 to gi...

You can find the area under this graph by evaluating the definite integral of y = f(x) with respect to x between x = a and x = b

Please note: An area below the x-axis has a negative value

Example:

Find the area under the graph of y = x^2 between x = 3 and x = 6

 

Step 1: Integrate x^2 to give 1/3x^3

Step 2: Find the definite integral by substituting in values of x 

Area = 1/3.6^3 - 1/3.3^3 = 72 - 9 = 63

see more

2 years ago

767 views
Send a message

All contact details will be kept confidential.

To give you a few options, we can ask three similar tutors to get in touch. More info.

Contact Jonathan

Still comparing tutors?

How do we connect with a tutor?

Where are they based?

How much does tuition cost?

How do tutorials work?

We use cookies to improve your site experience. By continuing to use this website, we'll assume that you're OK with this. Dismiss

mtw:mercury1:status:ok