Jonathan R. GCSE Maths tutor, A Level Maths tutor

Jonathan R.

£18 - £20 /hr

Currently unavailable: until 20/10/2016

Studying: Mechanical Engineering (Bachelors) - Warwick University

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About me

I am an engineering student at the University of Warwick. Maths has always been a passion of mine and I hope that my enthusiasm will allow you to get the most out of my tutorials.

I am a very friendly and understanding person. At primary school I was noted as a gifted and talented Maths student.

During the sessions I will focus on areas that you want to cover. First I will teach the concept until you have a strong understanding, before moving on to some exam style questions.

Maths is a great subject so I am sure you will find my tutorials fun but I will also do my best to make the sessions enjoyable.

I look forward to meeting you!

I am an engineering student at the University of Warwick. Maths has always been a passion of mine and I hope that my enthusiasm will allow you to get the most out of my tutorials.

I am a very friendly and understanding person. At primary school I was noted as a gifted and talented Maths student.

During the sessions I will focus on areas that you want to cover. First I will teach the concept until you have a strong understanding, before moving on to some exam style questions.

Maths is a great subject so I am sure you will find my tutorials fun but I will also do my best to make the sessions enjoyable.

I look forward to meeting you!

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Qualifications

SubjectQualificationGrade
MathsA-level (A2)A*
Further MathsA-level (A2)B
PhysicsA-level (A2)B

General Availability

Before 12pm12pm - 5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
MathsA Level£20 /hr
MathsGCSE£18 /hr

Questions Jonathan has answered

How can I find the area under the graph of y = f(x) between x = a and x = b?

You can find the area under this graph by evaluating the definite integral of y = f(x) with respect to x between x = a and x = b

Please note: An area below the x-axis has a negative value

Example:

Find the area under the graph of y = x^2 between x = 3 and x = 6

 

Step 1: Integrate x^2 to give 1/3x^3

Step 2: Find the definite integral by substituting in values of x 

Area = 1/3.6^3 - 1/3.3^3 = 72 - 9 = 63

You can find the area under this graph by evaluating the definite integral of y = f(x) with respect to x between x = a and x = b

Please note: An area below the x-axis has a negative value

Example:

Find the area under the graph of y = x^2 between x = 3 and x = 6

 

Step 1: Integrate x^2 to give 1/3x^3

Step 2: Find the definite integral by substituting in values of x 

Area = 1/3.6^3 - 1/3.3^3 = 72 - 9 = 63

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3 years ago

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