Currently unavailable: for regular students
Degree: Biology and Geology (Bachelors) - Durham University
After a year of being a Youth Assistant at Pegasus Theatre, Oxford I found that I had an enthusiasm for teaching. Wanting to pursue it more I began volunteering at the autism base in Cherwell School, Oxford in my penultimate year of sixth form. Here I was able to gather firsthand experience of one to one tuition as I helped them through their Key Stage courses. This allowed me to become more attentive to variations in a pupil’s behaviour and how to adapt my teaching method accordingly. Through this experience I hope to continue the enthusiasm I have for teaching onto MyTutorWeb.
My passion for sciences has run throughout my school career, following onto university. I believe covering the theory before developing understanding through exploring applied problems is essential as science is a knowledge you must build upon. This will also encourage independent thinking and prepares the student for questions they are very likely to experience in their examinations. I hope to reach the point where a student, faced with an unseen problem, can approach it from different angles with confidence in their ability.
I offer Maths, Biology and Geology including general science for 13 plus. Although reading Biology and Geology at university I take an elective module in Further Mathematics and so have not lost familiarity with the subject. I enjoy the subjects I offer thoroughly and would love the opportunity to pass on some of that passion to prospective pupils. If you have questions, feel free to mail me or book a “Meet the Tutor” session. I look forward to hearing from you. Callum :)
|Biology||A Level||£20 /hr|
|Geology||A Level||£20 /hr|
|Maths||A Level||£20 /hr|
|Maths||13 Plus||£18 /hr|
|Science||13 Plus||£18 /hr|
The Product Rule is used when differentiating two functions that are being multiplied together. It can be used by multiplying each function by the derivative of the other and adding.
If y=u*v then
dy/dx= u*dv/dx + v*du/dx
To illustrate this rule look at the example below:
u=x2 v=e3x du/dx= 2x dv/dx= 3e3x
Therefore dy/dx= (x2)*(3e3x)+ (e3x)*(2x)
dy/dx= 3x2e3x + 2xe3xsee more