Alexander W. GCSE Biology tutor, GCSE Maths tutor, A Level Maths tuto...

Alexander W.

£24 - £26 /hr

Mathematics (Integrated Masters) - Bristol University

5.0
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10 reviews

This tutor is also part of our Schools Programme. They are trusted by teachers to deliver high-quality 1:1 tuition that complements the school curriculum.

22 completed lessons

About me

Hello! I'm Alex and I'm a University of Bristol graduate, with a First Class Masters degree in Mathematics. I've always had a deep love of maths and I hope my tutorials can help you share some of that love. Studying maths can be interesting and even fun, but combined with exams can quickly become stressful and challenging.


Having been through the exam process myself, I know what works. I've tried so many revision techniques and ideas, and I know exactly which ones work best, whether that's for working to improve your understanding, or as a last minute boost to your exam grade.


Why pick me over other tutors?

I'm a friendly and patient tutor with years of teaching experience ranging from one-on-one maths tuition, volunteer work as a classroom assistant in local schools and as a gymnastics coach for a nationally ranked university team. I have a track record of helping students reach their potential, and I want to help you achieve your potential too.

 

Hello! I'm Alex and I'm a University of Bristol graduate, with a First Class Masters degree in Mathematics. I've always had a deep love of maths and I hope my tutorials can help you share some of that love. Studying maths can be interesting and even fun, but combined with exams can quickly become stressful and challenging.


Having been through the exam process myself, I know what works. I've tried so many revision techniques and ideas, and I know exactly which ones work best, whether that's for working to improve your understanding, or as a last minute boost to your exam grade.


Why pick me over other tutors?

I'm a friendly and patient tutor with years of teaching experience ranging from one-on-one maths tuition, volunteer work as a classroom assistant in local schools and as a gymnastics coach for a nationally ranked university team. I have a track record of helping students reach their potential, and I want to help you achieve your potential too.

 

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About my sessions

Every student benefits from different approaches and learning styles, and we can tailor the lessons so suit what works best for you.


In my experience, when learning a subject for an exam, it's important to break down the subject into three key steps:

1) Identify problem areas that students find difficult. (through students own self-awareness and testing)

2) Use targeted revision and learning to help bridge the gaps in student knowledge (whether this be through talking subjects over, lecture style sessions or example problems)

3) Use question practice and testing to re-inforce ideas and identify what needs further work.


I will work with you to come up with a strategy that helps you get the most of of our sessions. A lot can be covered in 55 minutes and I want to help you be prepared for both your exams and whatever future study in maths you are planning.


What next?

 

If you have any questions then please drop me a message or book a free video meeting. Let me know what you want to achieve out of your tuition, and what you're struggling with, and we can arrange tutoring that fits in with your schedule.

Every student benefits from different approaches and learning styles, and we can tailor the lessons so suit what works best for you.


In my experience, when learning a subject for an exam, it's important to break down the subject into three key steps:

1) Identify problem areas that students find difficult. (through students own self-awareness and testing)

2) Use targeted revision and learning to help bridge the gaps in student knowledge (whether this be through talking subjects over, lecture style sessions or example problems)

3) Use question practice and testing to re-inforce ideas and identify what needs further work.


I will work with you to come up with a strategy that helps you get the most of of our sessions. A lot can be covered in 55 minutes and I want to help you be prepared for both your exams and whatever future study in maths you are planning.


What next?

 

If you have any questions then please drop me a message or book a free video meeting. Let me know what you want to achieve out of your tuition, and what you're struggling with, and we can arrange tutoring that fits in with your schedule.

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Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

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Ratings & Reviews

5from 10 customer reviews
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Paul (Parent from Redditch)

May 3 2016

Very Helpful

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Paul (Parent from Redditch)

September 27 2016

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Paul (Parent from Redditch)

September 8 2016

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Paul (Parent from Redditch)

May 5 2016

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Qualifications

SubjectQualificationGrade
MathematicsA-level (A2)A*
Futher MathematicsA-level (A2)A
BiologyA-level (A2)A
MathematicsDegree (Masters)FIRST

General Availability

Pre 12pm12-5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
MathsA Level£26 /hr
MathsGCSE£24 /hr

Questions Alexander has answered

How do I sketch the graph y = (x^2 + 4*x + 2)/(3*x + 1)

This is an example of a rational function. So to sketch it, we need to know three things:
1) where it crosses the x and y axis
2) Where its turning points are, if it has any
3) Where its asymptotes are, if it has any.

Let's start with 1):
The graph crosses the y axis when x=0. So if x=0, then y=4/1 = 4. So the graph crosses the y axis at (0,4)

The graph crosses the x axis when y=0, which means the numerator of the fraction (x2 + 4*x + 4)/(3*x + 2) = 0. We see that the numerator can be factorised into (x + 2)2, which means that the numberator only equals zero when  x = -2. So the graph crosses the x axis at (-2,0)

Now onto 2):
Using the quotient rule, dy/dx = (3*x2 + 4*x - 4)/(3*x + 2)2
Now this is zero when the numerator is zero. We can factorise the numberator into (x+2)*(3*x - 2) to see that dy/dx is zero when x = -2 or x = 2/3. We could have also used the quadratic formula to work this out.

When x = -2, y = 0 as we already established. So this is where we cross the x axis and a turning point at the same time.

When x = 2/3, y = (2/3 + 2)2/(3*(2/3) + 1) = 64/27

by differentiating again to find dy/dx we can classify each stationary point: (-2,0) is a maximum and (2/3,64/27) is a minimum.

Now for part 3)
An asymptote is when the graph "shoots off to inifinity". So it occurs when the denominator of the function is zero. Here that only occurs when (3*x+1) = 0, or when x = -1/3.

So we have the parts of our graph we need to draw it. The curve comes in from the bottom right, touches the x axis at (-2,0) to change direction, shoots off to negative infinity along the line x=-1/3 (but never crossing it). Emerges from positive infinity the other side of the line x=-1/3, turns at the point (2/3,64/27) and swoops off the top right corner.

This is an example of a rational function. So to sketch it, we need to know three things:
1) where it crosses the x and y axis
2) Where its turning points are, if it has any
3) Where its asymptotes are, if it has any.

Let's start with 1):
The graph crosses the y axis when x=0. So if x=0, then y=4/1 = 4. So the graph crosses the y axis at (0,4)

The graph crosses the x axis when y=0, which means the numerator of the fraction (x2 + 4*x + 4)/(3*x + 2) = 0. We see that the numerator can be factorised into (x + 2)2, which means that the numberator only equals zero when  x = -2. So the graph crosses the x axis at (-2,0)

Now onto 2):
Using the quotient rule, dy/dx = (3*x2 + 4*x - 4)/(3*x + 2)2
Now this is zero when the numerator is zero. We can factorise the numberator into (x+2)*(3*x - 2) to see that dy/dx is zero when x = -2 or x = 2/3. We could have also used the quadratic formula to work this out.

When x = -2, y = 0 as we already established. So this is where we cross the x axis and a turning point at the same time.

When x = 2/3, y = (2/3 + 2)2/(3*(2/3) + 1) = 64/27

by differentiating again to find dy/dx we can classify each stationary point: (-2,0) is a maximum and (2/3,64/27) is a minimum.

Now for part 3)
An asymptote is when the graph "shoots off to inifinity". So it occurs when the denominator of the function is zero. Here that only occurs when (3*x+1) = 0, or when x = -1/3.

So we have the parts of our graph we need to draw it. The curve comes in from the bottom right, touches the x axis at (-2,0) to change direction, shoots off to negative infinity along the line x=-1/3 (but never crossing it). Emerges from positive infinity the other side of the line x=-1/3, turns at the point (2/3,64/27) and swoops off the top right corner.

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3 years ago

1095 views

Sasha has a bag containing 12 red beads, and 8 blue beads. She draws one bead from the bag at random. What is the probability that it is blue?

There are 12 + 8 = 20 beads in the bag in total.

If sasha draws a bead at random then she has 8 chances out of 20 possible beads that the bead is blue. So the probability that the bead is blue is 8/20 = 2/5

There are 12 + 8 = 20 beads in the bag in total.

If sasha draws a bead at random then she has 8 chances out of 20 possible beads that the bead is blue. So the probability that the bead is blue is 8/20 = 2/5

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3 years ago

1032 views

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