Dhrushee S. GCSE Maths tutor, 13 plus  Maths tutor, GCSE Economics tu...

Dhrushee S.

Currently unavailable: for regular students

Degree: Management (Bachelors) - St. Andrews Unversity University

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About me

Hi, my name is Dhrushee and I am an undergraduate Management student at St Andrews University

Having been on the other side of the tutoring process for many years, I would like the chance to pass on some of my accumulated study tips and knowledge to those of you going through the vital 13+/GCSE stages of your academic lives

My degree allows me to have a largely self-structured schedule so I can happily fit in tutorials during the week. Please contact me if you would like some help with Maths, Economics, Physics or Accounting- I have A Levels in Maths, Economics and Physics and have done degree-level Accounting and I hope to help guide you through any problem areas you may be facing with these subjects!

Subjects offered

SubjectLevelMy prices
Accounting GCSE £18 /hr
Economics GCSE £18 /hr
Maths GCSE £18 /hr
Physics GCSE £18 /hr
Maths 13 Plus £18 /hr

Qualifications

QualificationLevelGrade
PhysicsA-LevelA*
MathematicsA-LevelA
EconomicsA-LevelA
LatinA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: for regular students

Questions Dhrushee has answered

A rocket travels at 500m/s two minutes after its take-off. If it was initially stationary, calculate its acceleration. If the rocket has a mass of 1800kg, what force is required to give it an acceleration of 2m/s^2?

a) Acceleration is the rate of change of velocity of an object In this case, the equation that we will use to calculate it is  a = (v - u )/ t where v is the rocket's final speed, u is its initial speed, and t is the time taken Note: units of measurement  a: measured in m/s^2 v/u: measured...

a) Acceleration is the rate of change of velocity of an object

In this case, the equation that we will use to calculate it is 

a = (v - u )/ t

where v is the rocket's final speed, u is its initial speed, and t is the time taken

Note: units of measurement 

a: measured in m/s^2

v/u: measured in m/s

t: measured in s

Putting the given values into this equation, we find that 

acceleration = (500 - 0)m/s / (2x60)s = 4.17 m/s^2 (2dp)

- Hints: the initial speed of the rocket was 0 m/s at it was stationary to begin with, and we multiply 2 by sixty as we must convert time values from minutes into seconds. 

- I have included units in the calculation above- you dont need to do this at every stage of calculation but make sure you include units when giving a final answer!

b)  We can work out the second part of this question using Newtons's second law of motion F = m x a 

 F = 1800 x 2   = 3600 N ( or 3600 kgm/s^2) 

This law explains that the force (F) acting on an object is equal to the mass (m) of an object times its acceleration (a)

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1 year ago

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Factorise the following a) 8x + 6y b) 7xy + 3xzy c)5xyz - 20x^2y^2z

In order to factorise successfully, we have found the highest common factor for part a,b and c (the highest number that can be divided exactly into each of the terms) and placed these outside of the brackets a) 2 (4x+3y) b) xy (7 + 3z) c) 5xyz ( 1- 4xy) hint: for part b the order of the...

In order to factorise successfully, we have found the highest common factor for part a,b and c (the highest number that can be divided exactly into each of the terms) and placed these outside of the brackets

a) 2 (4x+3y)

b) xy (7 + 3z)

c) 5xyz ( 1- 4xy)

hint: for part b the order of the letters does not matter! 

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1 year ago

399 views
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