How do you use SOH CAH TOA?

If you have a right angled triangle, it is made up of a hypotenuse, adjacent and opposite. In SOH CAH TOA, the middle letter goes up, so when we use the equation, it will be sin=opposite/hypotenuse, etc. If, for example I've been asked to find the angle x and been told the opposite is length of 5 and the hypotenuse a length of 10, I can think about what I have been given. So I have the SOH. Therefore I need to do 5 (opposite) / 10 (hypotenuse). We now know sinx=0.5, so to find x we need to use sin-1(0.5)=30

KR

Related Maths GCSE answers

All answers ▸

Divide 711 in the ratio 4:5


How do you go about rearranging equations where the required subject appears on both sides? Such as making x the subject of 7x + a = 3x + b.


Show that the recurring decimal 0.0151515..=1/66 (4H)


How do I work out the exact value of a number which is expressed as an indice, for example 81^-1/4