Solve 6x^2 > 3 - 7x

First put everything to one side, 6x² + 7x - 3 > 0

Then factorise the LHS, (3x - 1)(2x + 3) > 0

Get two answers for x, x = 1/3 or x = -3/2

Then work out where the values of x will make the equation above correct, try a number inbetween your to values for x and sub it in and see what you get. For example if you sub in x = 0 you would get -3 which is not greater than 0, therefore you know the answer will be x > 1/3 and x < -3/2