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(2x+3)/(x-4) - (2x-8)/(2x+1) =1
(2x+3) (2x+1) = 4x^2 + 8x + 3 (2x-8) (x-4) = 2x^2 - 16x - 32 (4x^2+8x+3) - (2x^2-16x-32) = 1 2x^2 - 8x - 29 = 1 2x^2 - 8x - 30 = 0 x^2 - 4x - 15 = 0 Using the quadratic formula; x = 6.36 or x= -2.36 to 2dp
MA
Answered by
Masie A.
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Maths tutor
1880 Views
Solve the quadratic equation x^2 - 5x - 14 = 0, using factorisation.
Using factorisation, first we would have to look at the factors that multiply to make the last term, (-14). We know that they are +/- 7 and -/+2, and +/- 14 and -/+ 1, respectively. Now we have listed the fa...
ME
Answered by
Mram E.
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Maths tutor
8954 Views
Make a the subject of: (a+3)=(2a+7)/r
Equation: a+3 = (2a+7)/r First, we want to rearrange the equation, so that the 'r', which is the denominator of the right hand side, multiplies with (a+3), creating r(a+3) = 2a+7. Expanding this out, the equ...
JM
Answered by
Jana M.
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Maths tutor
14024 Views
How do I simplify multiplying potencies with the same base?
If for example you have g square x g cube, all you have to do is add up the potencies and put them in the same base, so in this case it will be g 5 . in the case of dividing potencies all you have to do is t...
GG
Answered by
Gonzalo G.
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Maths tutor
2277 Views
Solve: 7x - 20 = 3x + 4
7x = 3x + 24 4x = 24 x = 24 / 4 x = 6
AG
Answered by
Alex G.
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Maths tutor
2979 Views
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