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(2x+3)/(x-4) - (2x-8)/(2x+1) =1

(2x+3) (2x+1) = 4x^2 + 8x + 3 (2x-8) (x-4) = 2x^2 - 16x - 32 (4x^2+8x+3) - (2x^2-16x-32) = 1 2x^2 - 8x - 29 = 1 2x^2 - 8x - 30 = 0 x^2 - 4x - 15 = 0 Using the quadratic formula; x = 6.36 or x= -2.36 to 2dp
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Answered by Masie A. Maths tutor
1880 Views

Solve the quadratic equation x^2 - 5x - 14 = 0, using factorisation.

Using factorisation, first we would have to look at the factors that multiply to make the last term, (-14). We know that they are +/- 7 and -/+2, and +/- 14 and -/+ 1, respectively. Now we have listed the fa...
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Answered by Mram E. Maths tutor
8954 Views

Make a the subject of: (a+3)=(2a+7)/r

Equation: a+3 = (2a+7)/r First, we want to rearrange the equation, so that the 'r', which is the denominator of the right hand side, multiplies with (a+3), creating r(a+3) = 2a+7. Expanding this out, the equ...
JM
Answered by Jana M. Maths tutor
14024 Views

How do I simplify multiplying potencies with the same base?

If for example you have g square x g cube, all you have to do is add up the potencies and put them in the same base, so in this case it will be g 5 . in the case of dividing potencies all you have to do is t...
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Answered by Gonzalo G. Maths tutor
2277 Views

Solve: 7x - 20 = 3x + 4

7x = 3x + 24 4x = 24 x = 24 / 4 x = 6
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Answered by Alex G. Maths tutor
2979 Views