Solve the simultaneous equations 7x - 2y = 22 and 5x + 3y = 29

So we're going to solve this question using the elimination method. Now we can see that none of the x or y terms are the same in the 2 equations, so we have to make them the same. The easiet way to do this would be to find the LCM of the 2 coefficients of x, which is 35.

So:

  1. 7x-2y = 22    (Multiply equation by 5)

  2. 5x+3y = 29     (Multiply equation by 7)

This gives us:

  1. 35x-10y = 110

4.35x + 21y = 203

Solving equations 3 and 4 using the elimination method gives us y=3.  Substituting this value for y into equation 2 gives us x=4. 

RB
Answered by Raina B. Maths tutor

4799 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Simplify (x^5 * x^8)/(x^4 * x^4).


Which of these shapes has the most sides? Hexagon, Octagon, Rhombus, Trapezium


Prove that the difference of the square of two consecutive odd numbers is always a multiple of 8. [OCR GCSE June 2017 Paper 5]


Show 23/7 as a mixed number.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences