Factorise 2x^3=10x+12x^2

  1. Move everything to the same side: 2x^3-12X^2-10x=0 2.Take out a factor of 2x: 2x(x^2-6x-5)=0 3.Complete the square on the quadratic: 2x[(x-3)^2-14]=0
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Answered by Faye H. Maths tutor

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How do I solve a simultaneous equation like this: 2x-5y=3, 3x+2y=14 ?


solve for x by completing the square x^2 + 4x - 12


Make x the subject of the formula: 3x - 2 = y + 10


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