Solve to find x: 32x + 43 = -8x - 17

In order to find 'x', one must be able to isolate x on one side of the equation. This would be achieved firstly by adding +8x to both side of the equation:The left hand side would thus look like this: 40x + 43The right hand side would look like this: -17 (as -8x + 8x = 0)Now that we have x on one side of the equation, we can solve it to find the value of x.Our equation now looks like this: 40x + 43 = -17We next would subtract 43 from both sides.This leaves the left hand side of the equation as: 40x (as 43 - 43 = 0)It would also leave the right hand side as: -60 (-17 - 43 = -60)Now we have all the x's on one side, with a value on the other: 40x = -60From here, we can divide both sides by 40, leaving the equation as follows: x = -1.5 or x = -3/2.

FB
Answered by Francis B. Maths tutor

3488 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise x^2+2x-8


Functions question: f(x) = 3x + 2a; g(x) = ax + 6; fg(x) = 12x + b. a and b are constants; Work out the value of b


Kelly is trying to work out the two values of w for which 3w - w^3 = 2 Her values are 1 and -1 Are her values correct? You must show your working.


Solve algebraically the simultaneous equations: 6x=5-2y 12.5=3x+3y


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning