Solve these simultaneous Equations: 4y-2x=8 and 2x-y=7

So there are many different ways of solving this equation, one being that u can find out what one of the values of x and y are and then putting the answer of the value back in the equation. The way to isolate a value of x and y is by adding and subtracting the equation until the term is isolated. So for instance if you want to isolate the y value in 4y-2x=8 you can add 2x to both sides. By doing this you get:4y-2x+2x on one side and 8 +2x on the other. This means that the equation is now 4y=8+2x. This term cancelled down if everything is divided by two, so the equation becomes easier to deal with. By dividing both sides by two you will now have, 2y=4+x which can be further arranged to x=2y-4. This equation can now be applied to the other equation and gather like terms. So your second equation will go from 2x-y=7 to 2(2y-4)-y=7. Multiplying out the brackets and gathering like terms lead to 3y=15. Divide both sides by 3 and you get y=5. Substitute your Y value into the first equation to find your x value. So it becomes x=2(5)-4 which means X=6 and Y=5 you can substitute these values into either question to see if you are correct. 4(5)-2(6) is 20-12 which is 8. So you have found the values of two unkowns from simulating two equations