Solve simultaneously. x^2+y^2 = 25 ; y - 3x = 13

y = 3x + 1310x^2 + 78x + 169 = 2510x^2 +78x +144 = 0(5x+24)(2x+6) = 0x = -24/5 or -3y = -7/5 or 16

BH
Answered by Ben H. Maths tutor

2803 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you solve a simultaneous equation by 'substitution'?


Find the median, upper and lower quartiles of these numbers: 160, 390, 169, 175, 125, 420, 171, 250, 210, 258, 186, 243


Triangle PQR is a right angled triangle. PQ is the hypotenuse and is 5cm long and QR has length 3cm. What is the length of side PR? Show your working.


Calculate 27^(-3/2)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning