Solve the simultaneous equations: [4x-y=3] and [6x +2y=1]

(1) 4x-y=3(2) 6x+2y=1Eliminate y; (1) X 2 => (3) 8x-2y=6 Add (2) to (3) 8x - 2y = 6 +(6x + 2y) = 114x = 7x=1/2 If x=1/2 then,2-y=3 y= -1

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Simplify: 2x + 6y + 2y - x


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Given: ๐‘“(๐‘ฅ) = ๐‘Ž๐‘ฅ^3 + ๐‘๐‘ฅ^2 โˆ’ 3 and ๐‘“"(โˆ’2) = 0. If it is further given that the point (โˆ’3; 6) lies on the graph of ๐‘“. Show that ๐‘Ž = 1/3 and ๐‘ = 2.


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