(x+3)(x-4)(x+5) is identical to x^3 +ax^2 -17x+b. Find the value of a and the value of b.

Multiplying out the first two brackets gives (x^2-x-12)(x+5). Multiplying the remaining brackets gives x^3 + 4x^2 -17x - 60.

a = 4b = 60

AE

Related Maths GCSE answers

All answers ▸

Factorise 3x+12


Simplify fully (x^2*x^3)/x^4


Factorise the following expression: x^2-1


How do I know when a quadratic function crosses the y-axis?