So we're going to solve this question using the elimination method. Now we can see that none of the x or y terms are the same in the 2 equations, so we have to make them the same. The easiet way to do this would be to find the LCM of the 2 coefficients of x, which is 35.

So:

7x-2y = 22 (Multiply equation by 5)
5x+3y = 29 (Multiply equation by 7)

This gives us:

35x-10y = 110

4.35x + 21y = 203

Solving equations 3 and 4 using the elimination method gives us y=3. Substituting this value for y into equation 2 gives us x=4.

2x + y = 24, x - y = 6

Related Maths GCSE answers

How do you factorise a quadratic? Something like x^2 + 4x + 3

y = (3t + 1)/p, Where t = 3, and y = 2, what is the value of p?

Solve the simultaneous equations 7x - 2y = 22 and 5x + 3y = 29

Make r the subject of the formula: 1/r -1/p = 1/t