3y^2 + 10y + 3
3y2 + 10y + 33y2 = 3 * 1(3y + n) * (y + r)n * r = 3 hence to try whole numbers first n = 1 or 3 meaning r = 3 or 1 respectivey * n + 3y * r = 10yif n =1 and r = 3 then equivalent is 10y (correct)as all values work 3y2 +10y + 3 = (3y + 1) * (y + 3)y = -1/3 y = -3Alternative, use formula (-b +/- Sqrt(b2 -4ac))/2awhere ay2 + by + ca = 3 b =10 c = 3 y = -1/3 y = -3
JH
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