Completing the square is a method that can be used to solve the quadratic equation x^2+6x+14 in the form of (x+a)^2+b. The way we find a and b is as follows:For constant a, is found by halving the coefficient of x, so that a=6/2 where a=3For constant b, is found by taking the constant at the end of the quadratic, +14, and subtracting a^2 from it,so that b=14 - a^2 =14 - (3)^2 = 14 - 9 = 5 Now , let a=3 and b=5 and we can substitute them in the form of (x+a)^2+b Thus, the result for completing the square is:x^2+6x+14=(x+3)^2+5 Finally, we can check if the answer is true by (i) making sure that when we expand the result is equal to the quadratic equation(ii) substituting x with a number(1,2,3,..etc) and the result should be equal in both sides, LHS=RHS e.g let x=1, x^2+6x+14=(x+3)^2+5 (1)^2+6(1)+14=(1+3)^2+5 21=21 Therefore, is true.

Simplify the expression 5x + 6y -4x+ 7y

Related Maths GCSE answers

Tom's dad is 3 times older than him. In 15 years the sum of Tom's and his dad's ages will be equal to 102. How old are Tom and his dad now?

Show that the lines y=3x+7 and 2y–6x=8 are parallel. Do not use a graphical method.

Calculate the diameter of a circle with area 80cm^2 to two significant figures.

Write x^2+6x+14 in the form of (x+a)^2+b where a and b are constants to be determined.

We're here to help

Company Information

Popular Requests

© MyTutorWeb Ltd 2013–2025

CLICK CEOP