Please solve (x+3)(x+4)=20 for x

Expand the double bracket (x+3)(x+4) first: 1) (x)(x)= x^2, 2) (x)(4)=4x ,3) (3)(x)=3x, 4) (3)(4)=12write expanded equation:x^2+4x+3x+12=20simplify and equate the right hand side to zero:x^2+7x-8=0solve for x by factorising the quadratic equation:(x+8)(x-1)=0so the solutions for x are:x=-8 and x=1

CM
Answered by Caitilin M. Maths tutor

2252 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve for the coordinates where lines A and B intersect. A: y=x+4 B: y=0.5x+3.5


Solve the inequality 6y + 5 > 8


What is Pythagoras's theorem?


Solve x^2-x-12=0


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences