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Factorise 3π‘π‘ž4 βˆ’ 12π‘ž2𝑝6 fully.

3pq4 - 12q2p6 = 3(pq4-4q2p6) = 3p(q4-4q2p5) = 3pq2(q2-4p5)

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Answered by Ellica M. β€’ Maths tutor

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