Solve the following simultaneous equations: equation A 2y+3x=14 equation B y+2x=8

Step 1: make one term in both equations the sameHere we will multiply equation B by 2 so that there is a 2y in both equationsEquation C = 2 x equation B = 2y + 4x = 16
Step 2: Combine the equationsIf we take away equation A from equation C, we are left with 0y + x =2So x=2
Step 3: substitute known value back inIf x=2, equation A is 2y + 3(2)=14So 2y = 14-6 = 8So y=4
Step 4: CheckTo check we substitute the values back into equation B4 + 2(2) = 8 which is correct so we know our answers are correct!

RH
Answered by Rhiannon H. Maths tutor

1904 Views

See similar Maths 13 Plus tutors

Related Maths 13 Plus answers

All answers ▸

3/8 is the same as ?/24 ?


Solve the equation: 3x - 5.5 = 1/2


There is a right-angle triangle with hypothenus H = 5 cm and side A = 3 cm. Find the length of the third side B using Pythagoras' Theorem.


find the value of 2^3


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences