If the equation of a curve is x^2 + 9x + 8 = y, then differentiate it.

First we must establish how to differentiate terms individually. This is done by using the simple method of multiplying the X by the power, and subtracting one away from the power. To make it easier we will differentiate each term individually and then put the equation back together at the end. 1. x^2 2x^(2-1) =2x 2. 9x 19x^(1-1) = 9x^0 =91 = 9 3. 8 08^(0-1) = 0 Therefore dy/dx = 2x+9 This would be useful if the gradient needed to be found. To find the gradient at a point all you need to do is substitute in the X value.

TT
Answered by Tamara T. Further Mathematics tutor

2851 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

A curve has equation y = x^2 - 7x. P is a point on the curve, and the tangent to the curve at P has gradient 1. Work out the coordinates of P.


The curve C is given by the equation x^4 + x^2y + y^2 = 13. Find the value of dy/dx at the point (-1,3). (A-level)


A curve is defined by the equation y = (x + 3)(x – 4). Find the coordinates of the turning point of the curve.


Factorise the following quadratic x^2 - 8 + 16


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences