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How do you do integration by parts?

Split the equation into two : one that you are going to integrate, and the other one you want to differentiate. then, apply formula uv - integral(v * du)

Answered by Harvin I. • Maths tutor

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How do you do integration by parts?

Related Maths A Level answers

What's the deal with Integration by Parts?

By forming and solving a quadratic equation, solve the equation 5cosec(x) + cosec^2(x) = 2 - cot^2(x) in the interval 0<x<2pi, giving the values of x in radians to three significant figures.

Explain the basics of projectile motion

The curve C has equation y = (x^2 -4x - 2)^2. Point P lies on C and has coordinates (3,N). Find: a) the value of N. b) the equation of the tangent to C at the point P, in the form y=mx+c where m and c are constants to be found. c) determine d^2y/dx^2.

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How do you do integration by parts?

Related Maths A Level answers

What's the deal with Integration by Parts?

By forming and solving a quadratic equation, solve the equation 5*cosec(x) + cosec^2(x) = 2 - cot^2(x) in the interval 0<x<2*pi, giving the values of x in radians to three significant figures.

Explain the basics of projectile motion

The curve C has equation y = (x^2 -4x - 2)^2. Point P lies on C and has coordinates (3,N). Find: a) the value of N. b) the equation of the tangent to C at the point P, in the form y=mx+c where m and c are constants to be found. c) determine d^2y/dx^2.

We're here to help

Company Information

Popular Requests

© MyTutorWeb Ltd 2013–2025

CLICK CEOP

By forming and solving a quadratic equation, solve the equation 5cosec(x) + cosec^2(x) = 2 - cot^2(x) in the interval 0<x<2pi, giving the values of x in radians to three significant figures.