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So, what I would be looking for from students who are answering this questions are the application of differentiation techniques that they would have been taught at Year 12. The first step in answering th...

We are given y as a function of x, let's first compute dy/dx, and then solve the equation dy/dx =0. dy/dx = 9 -1/x^{2}. Then dy/dx = 0 is equivalent to 9 = 1/x^{2}. Taking x^{2} on...

QUOTIENT RULE: [u(x) / v(x)]' = [u'(x)v(x) - u(x)v'(x)] / v^{2}We have: u(x) = x^{4} - 1, hence u'(x) = 4x^{3}v(x) = x^{4} + 1, hence v'(x) = 4x^{3}

Since the equation for y is given in the format y=u/v, the use of the quotient rule is the easiest way to find the differential of this equation. The quotient rule states, (vu'-uv')/v^2 is equal to the di...

11 = 1/2 r^{2}RAB = x = rRr + r + x = 4x2r = 3rRR = 2/3r²R = 22r² = 33r = √33