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Why do the trig addition formulae work?

Try differentiating:sin(x)cos(z-x)+cos(x)sin(z-x)with respect to x and for constant z, then simply the derivative you deduce, then integrate throughout the simplified equation. See what happens!
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Why does 'x' need to be in radians to differentiate 'sin x'?

There are two definitions of the sine and cosine functions that anyone who uses contemporary maths, and I do mean anyone, uses silently or otherwise. The first is as follows:'Rotate the point (1,0) in Euclid...
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Differentiate y= (6x^2 - 5)^(3/2) with respect to x

Simplify the equation to y=u 3/2 where u = 6x 2 -5Use the chain ruledy/dx = dy/du x du/dxdy/du = (3/2)u 1/2 du/dx = 12x - 0Therefore dy/dx = (3/2)u 1/2 x 12xBut u = 6x 2 -5 so substitute that into the deriva...
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Simplify (3x^2 - 6x)/ (6x^3 - 19x^2 + 9x +10)

3x(x-2)/(2x+1)(x-2)(3x-5) 3x/(2x+1)(3x-5)
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Why is my answer incorrect?

Check for any silly mistakes, a lost negative or a simple arithmetic error. If you can’t find any, we’ll work through the question together and see where the method differs from yours. Then we will work out ...
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Answered by Zachary G. • Maths tutor
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