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A ball is hit horizontally at a height of 1.2 m and travels a horizontal distance of 5.0 m before reaching the ground. The ball is at rest when hit. Calculate the initial horizontal velocity given to the ball when it was hit.

Vertically: u=0 ms -1 s=1.2 m a=9.8 ms -2 s=ut + 0.5at 2 Therefore t = 0.49s Horizontally: t=0.49s s=5.0m speed = distance/time = 5.0/0.49 = 10.2 ms -1
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Answered by William W. • Physics tutor
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If photons are little particles emitted by atoms, where were they before they got emitted?

Eisntein showed that in his theory of relativity that energy and mass were no longer conserved, as they are in Newton's theory. This completely changes how we see particles. They are no longer fundamental bu...
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Answered by Uther S. • Physics tutor
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How would you prove the formula for the total capacitance of a system consisting of several capacitors linked in series?

The first thing you need to do is to decide what is kept constant within the system. (P.S. Essentially all problems in physics require conservation laws to some extent) In the case of components in series, y...
VG
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What is the photo-electric effect and what impact did it have on the development of Quantum Mechanics?

The photo-electric effect is the process in which a metal will emit electrons when light of a sufficiently high frequency is incident upon it, Before Einstein's description of the photo-electric effect the o...
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Answered by Oliver B. • Physics tutor
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A 12V lamp, 36W is switched on for 1 hour. Find the energy supplied by the battery.

E = P*t = 36 * 3600 = 1.3 * 10 5 J
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Answered by Rishabh A. • Physics tutor
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