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Find the equation for the tangent to the curve y^3 + x^3 + 3x^2 + 2y + 8 = 0 at the point (2,1)

As the tangent has the same gradient as the curve at the particular point, we need to find the gradient of the curve. To find the gradient we need to differentiate. Due to there being two variables in this e...
AE
Answered by Aphishek E. • Maths tutor
4832 Views

Solve x^3=1 giving all the roots between -pi<=theta<=pi in exponential form

x^3=1=e^2(pi) i k x=e^2(pi) i k/3 The three roots are k=0 x=1 k=1 x=e^2(pi)*i/3 k=-1 x=e^-2(pi) i k/3
AA
3834 Views

How do I approach the analysis of Elgar's first symphony?

Approaching an analysis of a large work such as a symphony can seem daunting at first, but the task can be made easy and enjoyable by setting out what features of the music to look for (such as harmony/ melo...
SG
Answered by Sydney G. • Music tutor
5774 Views

How do I find the nature of a stationary point

Firstly, note that a stationary point can either be a local maximum, local minimum or point of inflexion. Now suppose you have a differentiable function (a graph which has a unique gradient/derivative at eac...
CC
Answered by Curtis C. • Maths tutor
6884 Views

How does a capacitor work and how do I treat it in a circuit?

for a capacitor the equations you need to know are: Q=CV V=Vin*e^(t/RC) and E=1/2QV (with Q=charge/columbs, C= capacitance/Farads, V=voltage/volts, R=resitance/ohms, Vin=initial voltage when discharging/volt...
TM
Answered by Tom M. • Physics tutor
3599 Views