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If a curve has equation y = (-8/3)x^3 - 2x^2 + 4x + 18, find the two x coordinates of the stationary points of this curve.

The first step in solving this question is to differentiate equation y with respect to x. To differentiate a given 'x' term in an equation use the following method --> x n becomes nx (n-1) .y = (-8/3)x 3 ...
RT
Answered by Robyn T. • Maths tutor
3731 Views

A curve has equation y=x^2 + 2x +5. Find the coordinates of the point at which the gradient is equal to 1.

dy/dx= 2x+2 , gradient is equal to 1 so dy/dx also equals 1.1=2x+2-1=2xx=-1/2plug this value of x into the equation to get y=17/4
NL
Answered by Nikhil L. • Maths tutor
4305 Views

Find the derivative, dy/dx, of y = 8xcos(3x).

Let u= 8x then du/dx = 8Let v= cos(3x) then dv/dx = -3sin(3x)Therefore using the product rule: dy/dx = (cos(3x))(8) + (8x)(-3sin(3x))So dy/dx = 8cos(3x) - 24xsin(3x) .
JC
Answered by Joshua C. • Maths tutor
4020 Views

what is a standing wave and how is it formed ?

A standing wave is the interference of two sinusoidal waves travelling in opposite directions, confining the wave and its energy to a fixed position, creating nodes and anti nodes . nodes - points where the ...
DN
Answered by Danielle N. • Physics tutor
2272 Views

How do I tell if a curve has a maximum or a minimum?

Firstly we need to find the stationary point on the curve. We know what at a stationary point the gradient is zero so we will find the gradient of the curve. We do this by differentiation, when we have diffe...
CK
Answered by Charlotte K. • Maths tutor
7480 Views