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Solve algebraically the simultaneous equations: x^2 + y^2 = 25 and y - 3x = 13

Firstly, we need to use one equation to find an expression for one variable in terms of the other. Then we can substitute this expression into the other equation and solve for that variable. Using this numer...
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Answered by Gregor W. Maths tutor
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How will you help with my studies?

Having studied Spanish before I know what will help achieve the top grades.I can help with speaking practice and help develop your accent to sound more fluent and natural in your Spanish.I know about many di...
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Answered by Lucy C. Maths tutor
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Solve the two simultaneous equations. 1. x^2 + y^2 = 25, 2. y - 3x = 13

The way to solve simultaneous equations is to 'slot in' one equation into the other. For this question, we will use the information in equation 2 (after manipulating it) to solve equation one. First, we add ...
JL
Answered by Jazir L. Maths tutor
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Factorize x^2-x-20

Let's think backwards - what can we multiply to get this result?First, let's take a simpler example, an expression:(x-1)(x-2). We multiply 1st term of the 1st brackets by terms of the 2nd bracket and then we...
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Answered by Tomasz B. Maths tutor
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Jason and Mary leave their houses at the same time. They travel towards each other, Mary at 20km/h and Jason at 15km/h. They pass each other after an hour and a half. What was the original distance between them when they started?

Mary = 20km/h Jason = 15km/h s = d/t After 1.5 hours, Mary = 30km and Jason = 22.5km 30 + 22.5 = 52.5km
ZC
Answered by Zac C. Maths tutor
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