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Matt had 3 piles of coins, A, B and C. Altogether there was 72p. Pile B had twice as much as pile A. Pile C had three times as much as pile B.

x + 2x + 6x =729x=72x=72/9x=8
GA
Answered by Gideon A. • Maths tutor
4011 Views

There are 5 cards in order from smallest to largest, _ _ _ _ 8. The range is 6, the median is 6, the mode is 2, and the mean is 5. Find the numbers missing on the 4 blank cards.

The range is 6: The range is the difference between the smallest and largest value. So if the largest value is 8, then the smallest value is 8-6=2. The median is 6: Therefore the middle card must be 6. The m...
ET
Answered by Emily T. • Maths tutor
13302 Views

i) The point A on a graph is (6,-7), and point B is (3,5). Calculate the equation of the straight line that passes through both A and B. ii) Does the line pass through the point C (-2,26)?

i) Gradient (m) = ∆y/∆x. Therefore: m = (5-(-7))/(3-6) = (12)/(-3) = -4. Intercept (c) = 5-(3*(-4)) = 5+12 = 17. Therefore: y = -4x+17 ii) x = -2, y = 26. -4(-2) + 17 = 25. 25≠26, therefore the line does not...
AH
Answered by Adam H. • Maths tutor
3253 Views

How do I solve simultaneous equations? eg 1) 4x = 16 - 2y and 2) 3x + y = 9

With simultaneous equations it's important to write down all your working so you keep everything clear in your mind and don't get confused. Start by putting all the x and y of both equations on one side. In ...
SA
Answered by Sarah A. • Maths tutor
4255 Views

The length of a rectangle is five times the width. The area of the rectangle is 180cm^2. Work out the width of the rectangle.

Lets start off by calling the width of rectangle 'w'. The length of the rectangle is 5 times the width, or '5w'. The area of a rectangle can be worked out by multiplying the length by the width, i.e. 5w x w=...
HW
Answered by Hannah W. • Maths tutor
15754 Views