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Line Q goes through (0,5) and (4,7). Find the equation of Line Q in the form y = mx + c

M = Gradient M = (y 2 - y1)/(x2 - x 1 ) C = the 'y' intercept, where x = 0 Therefore, M = 2/4 = 1/2 = 0.5 y = 0.5x + 5
TD
Answered by Tutor105540 D. • Maths tutor
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PQRS is a parallelogram with P->Q=a and P->S=b. Find S->Q in terms of a and b. N is a point between S and Q, where SN:NQ is 3:2, find N->R

Vectors are special in that they have a direction as well as magnitude (size). To get from S->Q you can go from S->P = -b and then P->Q = a so S->Q = - b + a = a - b (remember underlining) To fin...
KB
Answered by Kristian B. • Maths tutor
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How can I draw a 30 degree angle without a protractor?

In the exam you will have a ruler and a pair of compasses, which you can use to construct a 60 degree angle by drawing two arcs. You can then draw two more arcs to bisect that 60 degree angle and make a 30 d...
ZC
Answered by Zoe C. • Maths tutor
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i) Make y the subject of the expression x = ((a-y)/b))^1/2 ii) Simplify fully (2x^2 − 8)/(4x^2 − 8x)

i) Square both sides of the expression to make x^2=(a-y)/b Multiply by b to remove the fraction from the equation and then rearrange to make y the subject. bx^2=a-y --> y=a-bx^2 ii) First factor out 2 fro...
OS
Answered by Oscar S. • Maths tutor
4774 Views

A semicircle has a diameter of 8cm, what it the area?

Area of a circle = pi × r 2 Area of semi-circle = 1/2(Area of circle) = 1/2(pi × r 2 ) Diameter = 2r r = 8÷2 = 4 Area of semi-circle = 1/2(pi × 4 2 )
AP
Answered by Annabelle P. • Maths tutor
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